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anonymous
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first off, \(\sqrt{49}=7\) right?

mar1e0721
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\[\sqrt{7} 49\]

anonymous
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so you are being asked for
\[\log_7(7)\]
which must be 1, because you are being asked "raise 7 to what power to get 7?" and the answer is 1

anonymous
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now i am lost

anonymous
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what is the base of your log? what is the input?

amorfide
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if you have this as base 10 then you are multiplying 7 by 7=49
log49
but if it is base 7, follow what @satellite73 said

mar1e0721
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log sqrt 7 bqase 49

mar1e0721
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Base**

amorfide
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lol what?

anonymous
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\[\log_{49}(\sqrt{7})\]?

anonymous
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base is 49, input is \(\sqrt{7}\) right?

anonymous
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trick is to try to write with exponents, because
\[\log_b(x)=y\iff b^y=x\] so you are trying to solve
\[49^y=\sqrt{7}\]

anonymous
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we see that \(49=7^2\) and \(\sqrt{7}=7^{\frac{1}{2}}\) so what you want is
\[7^{2y}=7^{\frac{1}{2}}\] or
\[2y=\frac{1}{2}\] or
\[y=\frac{1}{4}\]

anonymous
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meaning is simpler english that the number \(\sqrt{7}\) is the fourth root of 49