## mar1e0721 Group Title log 7 √ 49 one year ago one year ago

1. satellite73 Group Title

first off, $$\sqrt{49}=7$$ right?

2. mar1e0721 Group Title

$\sqrt{7} 49$

3. satellite73 Group Title

so you are being asked for $\log_7(7)$ which must be 1, because you are being asked "raise 7 to what power to get 7?" and the answer is 1

4. satellite73 Group Title

now i am lost

5. satellite73 Group Title

what is the base of your log? what is the input?

6. amorfide Group Title

if you have this as base 10 then you are multiplying 7 by 7=49 log49 but if it is base 7, follow what @satellite73 said

7. mar1e0721 Group Title

log sqrt 7 bqase 49

8. mar1e0721 Group Title

Base**

9. amorfide Group Title

lol what?

10. satellite73 Group Title

$\log_{49}(\sqrt{7})$?

11. satellite73 Group Title

base is 49, input is $$\sqrt{7}$$ right?

12. satellite73 Group Title

trick is to try to write with exponents, because $\log_b(x)=y\iff b^y=x$ so you are trying to solve $49^y=\sqrt{7}$

13. satellite73 Group Title

we see that $$49=7^2$$ and $$\sqrt{7}=7^{\frac{1}{2}}$$ so what you want is $7^{2y}=7^{\frac{1}{2}}$ or $2y=\frac{1}{2}$ or $y=\frac{1}{4}$

14. satellite73 Group Title

meaning is simpler english that the number $$\sqrt{7}$$ is the fourth root of 49