A community for students.
Here's the question you clicked on:
 0 viewing
mar1e0721
 2 years ago
log 7 √ 49
mar1e0721
 2 years ago
log 7 √ 49

This Question is Closed

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1first off, \(\sqrt{49}=7\) right?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1so you are being asked for \[\log_7(7)\] which must be 1, because you are being asked "raise 7 to what power to get 7?" and the answer is 1

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1what is the base of your log? what is the input?

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0if you have this as base 10 then you are multiplying 7 by 7=49 log49 but if it is base 7, follow what @satellite73 said

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[\log_{49}(\sqrt{7})\]?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1base is 49, input is \(\sqrt{7}\) right?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1trick is to try to write with exponents, because \[\log_b(x)=y\iff b^y=x\] so you are trying to solve \[49^y=\sqrt{7}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1we see that \(49=7^2\) and \(\sqrt{7}=7^{\frac{1}{2}}\) so what you want is \[7^{2y}=7^{\frac{1}{2}}\] or \[2y=\frac{1}{2}\] or \[y=\frac{1}{4}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1meaning is simpler english that the number \(\sqrt{7}\) is the fourth root of 49
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.