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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
first off, \(\sqrt{49}=7\) right?
 2 years ago

mar1e0721 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{7} 49\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so you are being asked for \[\log_7(7)\] which must be 1, because you are being asked "raise 7 to what power to get 7?" and the answer is 1
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
now i am lost
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
what is the base of your log? what is the input?
 2 years ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
if you have this as base 10 then you are multiplying 7 by 7=49 log49 but if it is base 7, follow what @satellite73 said
 2 years ago

mar1e0721 Group TitleBest ResponseYou've already chosen the best response.0
log sqrt 7 bqase 49
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[\log_{49}(\sqrt{7})\]?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
base is 49, input is \(\sqrt{7}\) right?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
trick is to try to write with exponents, because \[\log_b(x)=y\iff b^y=x\] so you are trying to solve \[49^y=\sqrt{7}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
we see that \(49=7^2\) and \(\sqrt{7}=7^{\frac{1}{2}}\) so what you want is \[7^{2y}=7^{\frac{1}{2}}\] or \[2y=\frac{1}{2}\] or \[y=\frac{1}{4}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
meaning is simpler english that the number \(\sqrt{7}\) is the fourth root of 49
 2 years ago
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