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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
first off, \(\sqrt{49}=7\) right?
 one year ago

mar1e0721 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{7} 49\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so you are being asked for \[\log_7(7)\] which must be 1, because you are being asked "raise 7 to what power to get 7?" and the answer is 1
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
now i am lost
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
what is the base of your log? what is the input?
 one year ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
if you have this as base 10 then you are multiplying 7 by 7=49 log49 but if it is base 7, follow what @satellite73 said
 one year ago

mar1e0721 Group TitleBest ResponseYou've already chosen the best response.0
log sqrt 7 bqase 49
 one year ago

amorfide Group TitleBest ResponseYou've already chosen the best response.0
lol what?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[\log_{49}(\sqrt{7})\]?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
base is 49, input is \(\sqrt{7}\) right?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
trick is to try to write with exponents, because \[\log_b(x)=y\iff b^y=x\] so you are trying to solve \[49^y=\sqrt{7}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
we see that \(49=7^2\) and \(\sqrt{7}=7^{\frac{1}{2}}\) so what you want is \[7^{2y}=7^{\frac{1}{2}}\] or \[2y=\frac{1}{2}\] or \[y=\frac{1}{4}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
meaning is simpler english that the number \(\sqrt{7}\) is the fourth root of 49
 one year ago
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