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Claire4christ

  • 3 years ago

Example A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. Solution: 1. Identify the variables. (0.02)(10) The quantity of robium in material 1 (5%)(x) The quantity of robium in material 2 (0.03)(x+10) The quantity of the desired mixture 2. Write an equation. 5% x + (0.02)(10) = (0.03)(x+10) The equation required. 3. Perform the Solution. 0.05x + 0.2 = .03x + 0.3 = 0.02x = 0.1 4. Write the answer. x = 5 The desired amount.

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  1. Claire4christ
    • 3 years ago
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    And i need help with these problem. An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds

  2. Claire4christ
    • 3 years ago
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    (0.15)(20) (10%)(x) (0.12)(x+20)

  3. Claire4christ
    • 3 years ago
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    so far right???

  4. mikaa_toxica13
    • 3 years ago
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    yess :)

  5. Claire4christ
    • 3 years ago
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    so next 10%x(0.15)(20)=(0.12)(x+20) right

  6. mikaa_toxica13
    • 3 years ago
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    yess. seems like you have it figured out.

  7. Claire4christ
    • 3 years ago
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    im confuse on last part

  8. andriod09
    • 3 years ago
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    What do you need now Claire?

  9. Claire4christ
    • 3 years ago
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    perform the solution

  10. mikaa_toxica13
    • 3 years ago
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    hrmmm i got .7 ?

  11. andriod09
    • 3 years ago
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    you mean solve the following: \[.1x(.15)(.20)=(.12)(x+20)?\]

  12. Claire4christ
    • 3 years ago
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    .10x+3=.12x+2.4=

  13. andriod09
    • 3 years ago
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    .10=.1 its 10, you don't need the 0, but it could be easier. to solve. \[.1x+3=.12x+2.4\]\[.1x+.6=.12x\]\[.6=.11x\]\[x=1.833\infty(3)\]

  14. Claire4christ
    • 3 years ago
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    so how did you get .6

  15. andriod09
    • 3 years ago
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    .06* my bad 1 sec. \[.1x+.06=.12x\][\.06=.11x\]\[1.833\infty(3)=x\] oddly,its the same answer.

  16. Claire4christ
    • 3 years ago
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    1.8 pounds???

  17. andriod09
    • 3 years ago
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    you could always use the percent bar method. that's easiest.

  18. Claire4christ
    • 3 years ago
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    so im confused how many pounds.

  19. andriod09
    • 3 years ago
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    A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. |dw:1349373397808:dw|

  20. Claire4christ
    • 3 years ago
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    And i need help with these problem. An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds

  21. andriod09
    • 3 years ago
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    i really hate percents just so you know. lol but ill help. just post ina new question, and don't forget to givethe best response medal.

  22. Claire4christ
    • 3 years ago
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    i will give bunch of them if you help me lol

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