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anonymous
 4 years ago
Example
A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium.
Solution:
1. Identify the variables.
(0.02)(10) The quantity of robium in material 1
(5%)(x) The quantity of robium in material 2
(0.03)(x+10) The quantity of the desired mixture
2. Write an equation.
5% x + (0.02)(10) = (0.03)(x+10) The equation required.
3. Perform the Solution.
0.05x + 0.2 = .03x + 0.3 = 0.02x = 0.1
4. Write the answer.
x = 5 The desired amount.
anonymous
 4 years ago
Example A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. Solution: 1. Identify the variables. (0.02)(10) The quantity of robium in material 1 (5%)(x) The quantity of robium in material 2 (0.03)(x+10) The quantity of the desired mixture 2. Write an equation. 5% x + (0.02)(10) = (0.03)(x+10) The equation required. 3. Perform the Solution. 0.05x + 0.2 = .03x + 0.3 = 0.02x = 0.1 4. Write the answer. x = 5 The desired amount.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And i need help with these problem. An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(0.15)(20) (10%)(x) (0.12)(x+20)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so next 10%x(0.15)(20)=(0.12)(x+20) right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yess. seems like you have it figured out.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im confuse on last part

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1What do you need now Claire?

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1you mean solve the following: \[.1x(.15)(.20)=(.12)(x+20)?\]

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1.10=.1 its 10, you don't need the 0, but it could be easier. to solve. \[.1x+3=.12x+2.4\]\[.1x+.6=.12x\]\[.6=.11x\]\[x=1.833\infty(3)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so how did you get .6

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1.06* my bad 1 sec. \[.1x+.06=.12x\][\.06=.11x\]\[1.833\infty(3)=x\] oddly,its the same answer.

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1you could always use the percent bar method. that's easiest.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so im confused how many pounds.

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. dw:1349373397808:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And i need help with these problem. An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds

andriod09
 4 years ago
Best ResponseYou've already chosen the best response.1i really hate percents just so you know. lol but ill help. just post ina new question, and don't forget to givethe best response medal.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i will give bunch of them if you help me lol
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