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Example
A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium.
Solution:
1. Identify the variables.
(0.02)(10) The quantity of robium in material 1
(5%)(x) The quantity of robium in material 2
(0.03)(x+10) The quantity of the desired mixture
2. Write an equation.
5% x + (0.02)(10) = (0.03)(x+10) The equation required.
3. Perform the Solution.
0.05x + 0.2 = .03x + 0.3 = 0.02x = 0.1
4. Write the answer.
x = 5 The desired amount.
 one year ago
 one year ago
Example A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. Solution: 1. Identify the variables. (0.02)(10) The quantity of robium in material 1 (5%)(x) The quantity of robium in material 2 (0.03)(x+10) The quantity of the desired mixture 2. Write an equation. 5% x + (0.02)(10) = (0.03)(x+10) The equation required. 3. Perform the Solution. 0.05x + 0.2 = .03x + 0.3 = 0.02x = 0.1 4. Write the answer. x = 5 The desired amount.
 one year ago
 one year ago

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Claire4christBest ResponseYou've already chosen the best response.0
And i need help with these problem. An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
(0.15)(20) (10%)(x) (0.12)(x+20)
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
so next 10%x(0.15)(20)=(0.12)(x+20) right
 one year ago

mikaa_toxica13Best ResponseYou've already chosen the best response.0
yess. seems like you have it figured out.
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
im confuse on last part
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
What do you need now Claire?
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
perform the solution
 one year ago

mikaa_toxica13Best ResponseYou've already chosen the best response.0
hrmmm i got .7 ?
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
you mean solve the following: \[.1x(.15)(.20)=(.12)(x+20)?\]
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
.10x+3=.12x+2.4=
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
.10=.1 its 10, you don't need the 0, but it could be easier. to solve. \[.1x+3=.12x+2.4\]\[.1x+.6=.12x\]\[.6=.11x\]\[x=1.833\infty(3)\]
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
so how did you get .6
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
.06* my bad 1 sec. \[.1x+.06=.12x\][\.06=.11x\]\[1.833\infty(3)=x\] oddly,its the same answer.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
you could always use the percent bar method. that's easiest.
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
so im confused how many pounds.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
A jeweler is using an alloy, a mixture of metals. He has 10 pounds of the alloy. 2% is the rare metal robium. He has another source which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. dw:1349373397808:dw
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
And i need help with these problem. An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 12% mixture. ______ pounds
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
i really hate percents just so you know. lol but ill help. just post ina new question, and don't forget to givethe best response medal.
 one year ago

Claire4christBest ResponseYou've already chosen the best response.0
i will give bunch of them if you help me lol
 one year ago
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