## gjhfdfg Group Title Rewrite the expression as a trigonometric function of a single angle measure. one year ago one year ago

1. gjhfdfg Group Title

$\frac{ \tan4 \theta + \tan 2 \theta }{ 1 - \tan 4 \theta + \tan 2 \theta }$

2. hsmt Group Title

hi. do you still need help with this one?

3. gjhfdfg Group Title

Yes, I'm so lost on how to solve it

4. hsmt Group Title

do you know the tangent addition formula?

5. hsmt Group Title

tan(a+b)=(tan a +tan b)/(1-tan a tanb)

6. hsmt Group Title

have you seen this formula before?

7. hsmt Group Title

now think about the angle a=4theta and the angle b=2theta. does this help?

8. gjhfdfg Group Title

Ive seen it but never used it,

9. hsmt Group Title

ah. well, your teacher is giving you the opportunity here

10. gjhfdfg Group Title

I'm confused on how I solve it with the this formula using the 'theta'

11. hsmt Group Title

ok. well, it is more recognition than solving. look at the form of the equation i gave you and the relation you wrote above. write this puppy as the tangent of the sum of the two angles you have been given (4theta and 2theta)

12. hsmt Group Title

it is good to ask questions if you are in doubt. :)

13. gjhfdfg Group Title

Sorry, If it takes to long to respond, I'm still confused a little so I'm trying to write it down so that would hopefully help me get it

14. hsmt Group Title

no problem. so the form of the equation is tan (a+b)=(tan a +tan b)/(1-tan a tan b). substitute for a 4theta and for b 2theta

15. gjhfdfg Group Title

So, tan 4theta + tan 2theta / 1- tan 4theta * tan 2.?

16. hsmt Group Title

we are interested in the left side. the tan (a+b) part. this condenses the mess you were given.

17. gjhfdfg Group Title

So 4 theta + 2 theta.?

18. hsmt Group Title

which becomes tan ?

19. gjhfdfg Group Title

You would add the 4 & 2 together & get 6 & 6 would be the tan wouldn't it.?

20. hsmt Group Title

perfect. yes!! so you tan 6theta, which is the trig function (tan) of a single angle 6theta.

21. gjhfdfg Group Title

Alright thank you for help.! :-) I understand this now.!