A community for students.
Here's the question you clicked on:
 0 viewing
znimon
 3 years ago
If I have x^5 81x and I want to find all the zeros here is how I go about that: x(x^481), x(x^43^4), x((x^2)^2(3^2)^2), x((x^23^2)(x^2+3^2), x((x3)(x+3)(x+3i)(x3i))
I am confused as whether the parentheses separating the (alone) x from the rest of the equation are necessary. For example 1(3*10), distribute the negative one is +30, but if I do what is in the parentheses first I get 30. I know the associative property and cumulative property as I understand them.
znimon
 3 years ago
If I have x^5 81x and I want to find all the zeros here is how I go about that: x(x^481), x(x^43^4), x((x^2)^2(3^2)^2), x((x^23^2)(x^2+3^2), x((x3)(x+3)(x+3i)(x3i)) I am confused as whether the parentheses separating the (alone) x from the rest of the equation are necessary. For example 1(3*10), distribute the negative one is +30, but if I do what is in the parentheses first I get 30. I know the associative property and cumulative property as I understand them.

This Question is Closed

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.11(3*10) = 30 it cannot be +30 distribution happens in addition/subtraction to multiplication, like a(b+c) = ac+ac

znimon
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks a ton, could you expand a little bit if possible on how that relates to the polynomial above.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1what you have done is correct x^581x= x((x3)(x+3)(x+3i)(x3i)) so zeros are 0,3,3,3i,3i

znimon
 3 years ago
Best ResponseYou've already chosen the best response.0I think I am confused because there is addition, subtraction, and multiplication inside the parentheses in the above polynomial.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1all the steps are correct, which step u have doubt in particular ?

znimon
 3 years ago
Best ResponseYou've already chosen the best response.0The need for all the parenthesis in the final step.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes, that paranthesis is needed x(x^4+81) must be there.

znimon
 3 years ago
Best ResponseYou've already chosen the best response.0Will you expand on that a little. I still feel stuck for some reason.

znimon
 3 years ago
Best ResponseYou've already chosen the best response.0Its not quite clear. I understand the difference now between 1(3+10) and 1(3*10)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1x^581x= x.x^481x Taking x common =x(x^481) if u don't put paranthesis , u will have x.x^481 which is x^581 which is incorrect

znimon
 3 years ago
Best ResponseYou've already chosen the best response.0Oh thanks that make a lot of sense.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1glad i could clear it :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.