anonymous
  • anonymous
If I have x^5 -81x and I want to find all the zeros here is how I go about that: x(x^4-81), x(x^4-3^4), x((x^2)^2-(3^2)^2), x((x^2-3^2)(x^2+3^2), x((x-3)(x+3)(x+3i)(x-3i)) I am confused as whether the parentheses separating the (alone) x from the rest of the equation are necessary. For example -1(3*10), distribute the negative one is +30, but if I do what is in the parentheses first I get -30. I know the associative property and cumulative property as I understand them.
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

hartnn
  • hartnn
-1(3*10) = -30 it cannot be +30 distribution happens in addition/subtraction to multiplication, like a(b+c) = ac+ac
anonymous
  • anonymous
Thanks a ton, could you expand a little bit if possible on how that relates to the polynomial above.
hartnn
  • hartnn
what you have done is correct x^5-81x= x((x-3)(x+3)(x+3i)(x-3i)) so zeros are 0,3,-3,3i,-3i

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I think I am confused because there is addition, subtraction, and multiplication inside the parentheses in the above polynomial.
hartnn
  • hartnn
all the steps are correct, which step u have doubt in particular ?
anonymous
  • anonymous
The need for all the parenthesis in the final step.
hartnn
  • hartnn
yes, that paranthesis is needed x(x^4+81) must be there.
anonymous
  • anonymous
Will you expand on that a little. I still feel stuck for some reason.
anonymous
  • anonymous
Its not quite clear. I understand the difference now between -1(3+10) and -1(3*10)
anonymous
  • anonymous
@hartnn
hartnn
  • hartnn
x^5-81x= x.x^4-81x Taking x common =x(x^4-81) if u don't put paranthesis , u will have x.x^4-81 which is x^5-81 which is incorrect
anonymous
  • anonymous
Oh thanks that make a lot of sense.
hartnn
  • hartnn
glad i could clear it :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.