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hba

Value of x in log5x = 4logx5 is

  • one year ago
  • one year ago

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  1. hba
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    @hartnn

    • one year ago
  2. hartnn
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    draw the question

    • one year ago
  3. hba
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    Ok

    • one year ago
  4. hba
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    Ok\[\log_{5}x=4\log_{x}5\]

    • one year ago
  5. hartnn
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    use : \(\huge\log_ab= \frac{log b}{loga}\)

    • one year ago
  6. hba
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    logx/log5=4log5/logx whats next ??

    • one year ago
  7. hartnn
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    try to bring log x on one side and other terms on other side of = sign

    • one year ago
  8. hba
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    (logx)(logx)=4(log5)(log5)

    • one year ago
  9. hba
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    What do i do next ?? @hartnn

    • one year ago
  10. hartnn
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    yup, take square root on both sides after writing log x . logx as (log x)^2

    • one year ago
  11. hba
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    logx=2log5

    • one year ago
  12. hartnn
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    now use \(nlog x =log x^n\)

    • one year ago
  13. hba
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    logx=log5^2

    • one year ago
  14. hartnn
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    what is 5^2 ?

    • one year ago
  15. hba
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    25

    • one year ago
  16. hba
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    logx=log25

    • one year ago
  17. hba
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    so x=25

    • one year ago
  18. hartnn
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    yes..

    • one year ago
  19. akash_809
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    5 ^4

    • one year ago
  20. hba
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    but i think i will get 2 answers

    • one year ago
  21. akash_809
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    \[\log_{x}5^a = a \log_{x}5 \]

    • one year ago
  22. hartnn
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    how 2 ?

    • one year ago
  23. akash_809
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    use this so u will get x = 5^4 =625 , do u get it @hba

    • one year ago
  24. hba
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    25 and 1/25

    • one year ago
  25. hba
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    @akash_809 Please dont confuse me

    • one year ago
  26. hba
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    Options given .A) 25, 1/25 B) 1, -1 C) 0, 1 D) 2, 3 E) 4, 5

    • one year ago
  27. hartnn
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    when u take square root, u also get -*minus* so u also get 1/25

    • one year ago
  28. hba
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    Ok Boss Thanks :)

    • one year ago
  29. hartnn
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    welcomes :)

    • one year ago
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