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hba

  • 2 years ago

Value of x in log5x = 4logx5 is

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  1. hba
    • 2 years ago
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    @hartnn

  2. hartnn
    • 2 years ago
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    draw the question

  3. hba
    • 2 years ago
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    Ok

  4. hba
    • 2 years ago
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    Ok\[\log_{5}x=4\log_{x}5\]

  5. hartnn
    • 2 years ago
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    use : \(\huge\log_ab= \frac{log b}{loga}\)

  6. hba
    • 2 years ago
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    logx/log5=4log5/logx whats next ??

  7. hartnn
    • 2 years ago
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    try to bring log x on one side and other terms on other side of = sign

  8. hba
    • 2 years ago
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    (logx)(logx)=4(log5)(log5)

  9. hba
    • 2 years ago
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    What do i do next ?? @hartnn

  10. hartnn
    • 2 years ago
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    yup, take square root on both sides after writing log x . logx as (log x)^2

  11. hba
    • 2 years ago
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    logx=2log5

  12. hartnn
    • 2 years ago
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    now use \(nlog x =log x^n\)

  13. hba
    • 2 years ago
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    logx=log5^2

  14. hartnn
    • 2 years ago
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    what is 5^2 ?

  15. hba
    • 2 years ago
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    25

  16. hba
    • 2 years ago
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    logx=log25

  17. hba
    • 2 years ago
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    so x=25

  18. hartnn
    • 2 years ago
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    yes..

  19. akash_809
    • 2 years ago
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    5 ^4

  20. hba
    • 2 years ago
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    but i think i will get 2 answers

  21. akash_809
    • 2 years ago
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    \[\log_{x}5^a = a \log_{x}5 \]

  22. hartnn
    • 2 years ago
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    how 2 ?

  23. akash_809
    • 2 years ago
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    use this so u will get x = 5^4 =625 , do u get it @hba

  24. hba
    • 2 years ago
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    25 and 1/25

  25. hba
    • 2 years ago
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    @akash_809 Please dont confuse me

  26. hba
    • 2 years ago
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    Options given .A) 25, 1/25 B) 1, -1 C) 0, 1 D) 2, 3 E) 4, 5

  27. hartnn
    • 2 years ago
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    when u take square root, u also get -*minus* so u also get 1/25

  28. hba
    • 2 years ago
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    Ok Boss Thanks :)

  29. hartnn
    • 2 years ago
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    welcomes :)

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