hba
  • hba
Value of x in log5x = 4logx5 is
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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hba
  • hba
@hartnn
hartnn
  • hartnn
draw the question
hba
  • hba
Ok

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hba
  • hba
Ok\[\log_{5}x=4\log_{x}5\]
hartnn
  • hartnn
use : \(\huge\log_ab= \frac{log b}{loga}\)
hba
  • hba
logx/log5=4log5/logx whats next ??
hartnn
  • hartnn
try to bring log x on one side and other terms on other side of = sign
hba
  • hba
(logx)(logx)=4(log5)(log5)
hba
  • hba
What do i do next ?? @hartnn
hartnn
  • hartnn
yup, take square root on both sides after writing log x . logx as (log x)^2
hba
  • hba
logx=2log5
hartnn
  • hartnn
now use \(nlog x =log x^n\)
hba
  • hba
logx=log5^2
hartnn
  • hartnn
what is 5^2 ?
hba
  • hba
25
hba
  • hba
logx=log25
hba
  • hba
so x=25
hartnn
  • hartnn
yes..
anonymous
  • anonymous
5 ^4
hba
  • hba
but i think i will get 2 answers
anonymous
  • anonymous
\[\log_{x}5^a = a \log_{x}5 \]
hartnn
  • hartnn
how 2 ?
anonymous
  • anonymous
use this so u will get x = 5^4 =625 , do u get it @hba
hba
  • hba
25 and 1/25
hba
  • hba
@akash_809 Please dont confuse me
hba
  • hba
Options given .A) 25, 1/25 B) 1, -1 C) 0, 1 D) 2, 3 E) 4, 5
hartnn
  • hartnn
when u take square root, u also get -*minus* so u also get 1/25
hba
  • hba
Ok Boss Thanks :)
hartnn
  • hartnn
welcomes :)

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