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Lukecrayonz

  • 2 years ago

How many imaginary and real zeros the function have? f(x)=x^4+12x^3+37x^2+12x+36

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  1. ganeshie8
    • 2 years ago
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    Descartes rule of signs, first find out # of positive and negative real zeroes

  2. Lukecrayonz
    • 2 years ago
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    Is it 4 imaginary?

  3. ganeshie8
    • 2 years ago
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    u got 0 positive roots, and 4/2/0 negative zeroes is it ?

  4. ganeshie8
    • 2 years ago
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    if u see 4 sign changes in f(-x), then there CAN be 4 or 2 or 0 negative zeroes.

  5. ganeshie8
    • 2 years ago
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    |dw:1349376159150:dw|

  6. ganeshie8
    • 2 years ago
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    thats one set of possible # of roots, we need to decrease -ve zeores by 2, and find other possible sets.

  7. estudier
    • 2 years ago
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    What does your question say exactly? Are you supposed to identify how many or just the possible combinations?

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