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Lukecrayonz
 4 years ago
How many imaginary and real zeros the function have?
f(x)=x^4+12x^3+37x^2+12x+36
Lukecrayonz
 4 years ago
How many imaginary and real zeros the function have? f(x)=x^4+12x^3+37x^2+12x+36

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ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0Descartes rule of signs, first find out # of positive and negative real zeroes

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0u got 0 positive roots, and 4/2/0 negative zeroes is it ?

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0if u see 4 sign changes in f(x), then there CAN be 4 or 2 or 0 negative zeroes.

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349376159150:dw

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0thats one set of possible # of roots, we need to decrease ve zeores by 2, and find other possible sets.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What does your question say exactly? Are you supposed to identify how many or just the possible combinations?
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