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Lukecrayonz
How many imaginary and real zeros the function have? f(x)=x^4+12x^3+37x^2+12x+36
Descartes rule of signs, first find out # of positive and negative real zeroes
u got 0 positive roots, and 4/2/0 negative zeroes is it ?
if u see 4 sign changes in f(-x), then there CAN be 4 or 2 or 0 negative zeroes.
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thats one set of possible # of roots, we need to decrease -ve zeores by 2, and find other possible sets.
What does your question say exactly? Are you supposed to identify how many or just the possible combinations?