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gjhfdfg Group Title Verify the identity. Justify each step. tan (theta) + cot (theta) = 1 / sin (theta) cos (theta) one year ago one year ago

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1. AbhimanyuPudi Group Title

tan(theta) = sin(theta) / cos(theta) and cot(theta) = cos(theta) / sin(theta) Substitute these in the above equation and you will prove it right...Any doubt?

2. gjhfdfg Group Title

How would I substitute the 'sin'.?

3. AbhimanyuPudi Group Title

tanx + cotx = sinx/cosx + cosx/sinx = $( \sin x ^{2} + \cos ^{2} ) / (\sin x)(\cos x) = 1/(\sin x)(\cos x)$

4. gjhfdfg Group Title

I'm so confused

5. AbhimanyuPudi Group Title

we know, $(\sin x) ^{2} + (\cos x) ^{2} = 1$

6. zepdrix Group Title

|dw:1349378735588:dw|

7. zepdrix Group Title

|dw:1349379018546:dw| This could be your next step perhaps. :) Still confused?

8. zepdrix Group Title

Yah you need to remember a lot of identities in trig, spend a good amount of time committing them to memory. Cause you'll do a lot of switching them back and forth in your class! :O

9. gjhfdfg Group Title

I kinda get it.? Sorry math is my weakest subject. :/ Some of the steps confuse me a little bit, I'm going to look at them again

10. gjhfdfg Group Title

So since tan (theta) = sin (theta) / cos (theta) , and cot (theta) = cos (theta) / sin (theta) , sin (theta) / cos (theta) + cos (theta) / sin (theta) must equal to 1 / sin (theta) cos (theta), then you get the common denominator of 1 / sin (theta) cos (theta) . Is this basically what your saying.?

11. zepdrix Group Title

|dw:1349382130808:dw| Yes :) Justifying each step. The last step would look like this. Justifying it with "Since" before we actually make the substitution with the identity.