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gjhfdfg
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Verify the identity. Justify each step.
tan (theta) + cot (theta) = 1 / sin (theta) cos (theta)
 2 years ago
 2 years ago
gjhfdfg Group Title
Verify the identity. Justify each step. tan (theta) + cot (theta) = 1 / sin (theta) cos (theta)
 2 years ago
 2 years ago

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AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
tan(theta) = sin(theta) / cos(theta) and cot(theta) = cos(theta) / sin(theta) Substitute these in the above equation and you will prove it right...Any doubt?
 2 years ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
How would I substitute the 'sin'.?
 2 years ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
tanx + cotx = sinx/cosx + cosx/sinx = \[( \sin x ^{2} + \cos ^{2} ) / (\sin x)(\cos x) = 1/(\sin x)(\cos x)\]
 2 years ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
I'm so confused
 2 years ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
we know, \[(\sin x) ^{2} + (\cos x) ^{2} = 1\]
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
dw:1349378735588:dw
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
dw:1349379018546:dw This could be your next step perhaps. :) Still confused?
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
Yah you need to remember a lot of identities in trig, spend a good amount of time committing them to memory. Cause you'll do a lot of switching them back and forth in your class! :O
 2 years ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
I kinda get it.? Sorry math is my weakest subject. :/ Some of the steps confuse me a little bit, I'm going to look at them again
 2 years ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
So since tan (theta) = sin (theta) / cos (theta) , and cot (theta) = cos (theta) / sin (theta) , sin (theta) / cos (theta) + cos (theta) / sin (theta) must equal to 1 / sin (theta) cos (theta), then you get the common denominator of 1 / sin (theta) cos (theta) . Is this basically what your saying.?
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.2
dw:1349382130808:dw Yes :) Justifying each step. The last step would look like this. Justifying it with "Since" before we actually make the substitution with the identity.
 2 years ago
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