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Stephen2012

  • 3 years ago

8r^2-13r+5=(4r+?)(2r+?)

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  1. Stephen2012
    • 3 years ago
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    Can someone help

  2. znimon
    • 3 years ago
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    \[ax^2 + bx + c, (-b \pm \sqrt{b^2-4ac} )/2a\]

  3. znimon
    • 3 years ago
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    (x-1)(8x-5)

  4. znimon
    • 3 years ago
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    This turns out that the zeros aren't clean whole number so it is much better to use the quadratic formula in these sort of cases. Zeros = 5/8 and 1

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