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square both sides first... what do you get?

\[(\sqrt{6x-8})^2 = x^2\]

when you square a square root, you get back whatever is in the radicand...

\[ \left(\sqrt{\text{SOMETHING}}\right)^2 = \text{SOMETHING} \]

\(\large (\sqrt{radicand})^2 = radicand \)

\[x^2 = x^2 \]

\[6x-8 = x^2\]

What should you do next?

You could do that but you want to get the x's together because you are solving for x.

Well the most efficient thing to do would be to subtract 6x from both , right?

So whats next?

6x-6x = 0
Remember "like terms"

\[-8 = x^2 - 6x\]

still need help?

bye... i'll continue...