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Zekarias
 2 years ago
Best ResponseYou've already chosen the best response.0\[\cot(x\pi/2)=\tan(\pi/2(x\pi/2))=\tan(x)=\tan(x)\]

Kashan
 2 years ago
Best ResponseYou've already chosen the best response.0cot ( theta  pi / 2 )= cos ( theta  pi / 2 ) / sin ( theta  pi / 2 ) cos ( theta  pi / 2 )= cos(theta) cos (pi/2) + sin(theta) sin (pi/2) = cos(theta) (0) + sin(theta) (1) = sin(theta) sin ( theta  pi / 2 )= sin(theta) cos(pi/2)  cos(theta) sin(pi/2) = sin(theta) (0)  cos(theta) (1) = cos(theta) so you get, cot ( theta  pi / 2 )= sin(theta) / cos(theta) cot ( theta  pi / 2 )= tan(theta)

Zekarias
 2 years ago
Best ResponseYou've already chosen the best response.0For any CO  trigonometric functions m(x) and com(x), this property is always true.\[m(x)=co m(\pi/2x)=co m(x\pi/2).....or ..vise..versaif ..m(x)..is ..even\]\[m(x)=co m(\pi/2x)=co m(x\pi/2).....or ..vise..versaif ..m(x)..is ..odd\]

Zekarias
 2 years ago
Best ResponseYou've already chosen the best response.0The first one is for even function and the second one for odd.

gjhfdfg
 2 years ago
Best ResponseYou've already chosen the best response.0Alright I get it thank you.!
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