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ZekariasBest ResponseYou've already chosen the best response.0
\[\cot(x\pi/2)=\tan(\pi/2(x\pi/2))=\tan(x)=\tan(x)\]
 one year ago

KashanBest ResponseYou've already chosen the best response.0
cot ( theta  pi / 2 )= cos ( theta  pi / 2 ) / sin ( theta  pi / 2 ) cos ( theta  pi / 2 )= cos(theta) cos (pi/2) + sin(theta) sin (pi/2) = cos(theta) (0) + sin(theta) (1) = sin(theta) sin ( theta  pi / 2 )= sin(theta) cos(pi/2)  cos(theta) sin(pi/2) = sin(theta) (0)  cos(theta) (1) = cos(theta) so you get, cot ( theta  pi / 2 )= sin(theta) / cos(theta) cot ( theta  pi / 2 )= tan(theta)
 one year ago

ZekariasBest ResponseYou've already chosen the best response.0
For any CO  trigonometric functions m(x) and com(x), this property is always true.\[m(x)=co m(\pi/2x)=co m(x\pi/2).....or ..vise..versaif ..m(x)..is ..even\]\[m(x)=co m(\pi/2x)=co m(x\pi/2).....or ..vise..versaif ..m(x)..is ..odd\]
 one year ago

ZekariasBest ResponseYou've already chosen the best response.0
The first one is for even function and the second one for odd.
 one year ago

gjhfdfgBest ResponseYou've already chosen the best response.0
Alright I get it thank you.!
 one year ago
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