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Ice_Wolf Group Title

I Need Help With This Problem!?!?!

  • one year ago
  • one year ago

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  1. Ice_Wolf Group Title
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    • one year ago
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  2. TheWriter Group Title
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    I don't remember how to do that. Sorry.

    • one year ago
  3. satellite73 Group Title
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    \(a^0=1\) might help

    • one year ago
  4. TheWriter Group Title
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    Nope, still don't remember how.

    • one year ago
  5. Ice_Wolf Group Title
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    It's Ok. Thanks Anyways.

    • one year ago
  6. futrchamp Group Title
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    Okay. a^1 is a, by definition. a^0 is 1 (this can be seen by using the laws of dividing exponents, since any number divided by itself is 1) a^-n is 1/a^n (This is because raising one power is multiplying a by itself, but subtracting 1 from the exponent of a^0 is 1/a, and so on) 1/a^-n is a^n, by the same logic.

    • one year ago
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