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anonymous
 3 years ago
a ball, starting from rest, requires a speed of 10 m/s when a force is applied for a distance of 40 m. if the ball has a mass of 5 kg, what is the force being applied?
anonymous
 3 years ago
a ball, starting from rest, requires a speed of 10 m/s when a force is applied for a distance of 40 m. if the ball has a mass of 5 kg, what is the force being applied?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, you can tell this is an energy problem, as opposed to an acceleration problem, because they give you force and distance as opposed to force and time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So you want to first find the kinetic energy of the ball.\[\Large E_{kinetic}=\frac{1}{2}mv^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now work is just the change in energy. Since the ball started at rest, it started at 0 energy so\[\Large E_{work} = E_{kinetic}  0 = E_{kinetic}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Work is force times distance so: \[\Large E_{work}=Fd\]\[\Large F = \frac{1}{d}E_{work}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Combine it all together and we get:\[F=\frac{1}{d}\frac{1}{2}mv^2\]Where \(d = 20m\), \(m=5kg\), and \(v=10m/s\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@raytiller1 I couldn't have made it any easier for you without giving you the answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so \[\frac{ 1 }{ 20 }\frac{ 1 }{ 2 } 20(10)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You need to square velocity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You also need to look at my formula and understand what I did.
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