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raytiller1
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a ball, starting from rest, requires a speed of 10 m/s when a force is applied for a distance of 40 m. if the ball has a mass of 5 kg, what is the force being applied?
 one year ago
 one year ago
raytiller1 Group Title
a ball, starting from rest, requires a speed of 10 m/s when a force is applied for a distance of 40 m. if the ball has a mass of 5 kg, what is the force being applied?
 one year ago
 one year ago

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wio Group TitleBest ResponseYou've already chosen the best response.0
Okay, you can tell this is an energy problem, as opposed to an acceleration problem, because they give you force and distance as opposed to force and time.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
So you want to first find the kinetic energy of the ball.\[\Large E_{kinetic}=\frac{1}{2}mv^2\]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Now work is just the change in energy. Since the ball started at rest, it started at 0 energy so\[\Large E_{work} = E_{kinetic}  0 = E_{kinetic}\]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Work is force times distance so: \[\Large E_{work}=Fd\]\[\Large F = \frac{1}{d}E_{work}\]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Combine it all together and we get:\[F=\frac{1}{d}\frac{1}{2}mv^2\]Where \(d = 20m\), \(m=5kg\), and \(v=10m/s\)
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
@raytiller1 I couldn't have made it any easier for you without giving you the answer.
 one year ago

raytiller1 Group TitleBest ResponseYou've already chosen the best response.0
so \[\frac{ 1 }{ 20 }\frac{ 1 }{ 2 } 20(10)\]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
You need to square velocity
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
You also need to look at my formula and understand what I did.
 one year ago
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