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raytiller1
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a ball, starting from rest, requires a speed of 10 m/s when a force is applied for a distance of 40 m. if the ball has a mass of 5 kg, what is the force being applied?
 2 years ago
 2 years ago
raytiller1 Group Title
a ball, starting from rest, requires a speed of 10 m/s when a force is applied for a distance of 40 m. if the ball has a mass of 5 kg, what is the force being applied?
 2 years ago
 2 years ago

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wio Group TitleBest ResponseYou've already chosen the best response.0
Okay, you can tell this is an energy problem, as opposed to an acceleration problem, because they give you force and distance as opposed to force and time.
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
So you want to first find the kinetic energy of the ball.\[\Large E_{kinetic}=\frac{1}{2}mv^2\]
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Now work is just the change in energy. Since the ball started at rest, it started at 0 energy so\[\Large E_{work} = E_{kinetic}  0 = E_{kinetic}\]
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Work is force times distance so: \[\Large E_{work}=Fd\]\[\Large F = \frac{1}{d}E_{work}\]
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Combine it all together and we get:\[F=\frac{1}{d}\frac{1}{2}mv^2\]Where \(d = 20m\), \(m=5kg\), and \(v=10m/s\)
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
@raytiller1 I couldn't have made it any easier for you without giving you the answer.
 2 years ago

raytiller1 Group TitleBest ResponseYou've already chosen the best response.0
so \[\frac{ 1 }{ 20 }\frac{ 1 }{ 2 } 20(10)\]
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
You need to square velocity
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
You also need to look at my formula and understand what I did.
 2 years ago
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