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omnomnom
 3 years ago
A stone is dropped from the roof of a tall building. A person measures the speed of the stone to be 49 m/sec when it hits the ground. The height of the building is closest to:
Select one:
a. 24 meters.
b. 49 meters.
c. 122 meters.
d. 245 meters.
omnomnom
 3 years ago
A stone is dropped from the roof of a tall building. A person measures the speed of the stone to be 49 m/sec when it hits the ground. The height of the building is closest to: Select one: a. 24 meters. b. 49 meters. c. 122 meters. d. 245 meters.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[mgh = \frac{ 1 }{ 2 }mv ^{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can subtract the mass from both sides which shows that everything falls at the same rate

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so if you plug in the velovity and solve for h which is the height

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is this for conservation of energy

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0No this is only for the height of the building

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The formula I gave you is the conservation of energy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In this case \(g\) is the gravitational acceleration we talked about in the previous problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You cannot solve this with kinematics there are too many unknowns

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you mean you can't solve it with kinematics?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah I guess you could solve for time in the acceleration then plug it in the average velocity.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I was talking about the \(g\) in your formula.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Though technically speaking, depending on whether they are on the 'energy' part or the 'kinematic' part of the course decides which method they should use.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is why I was asking

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Last question was a 'kinematic' one so maybe it must be kinematics.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0acceleration of gravity = velocity final minus velocity inital divided by time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@omnomnom Have you talked about work or energy in your class yet?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Like potential energy or kinetic energy?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It is something you will learn in the future, most likely.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes solve for time then plug into \[\frac{ d }{ t }=\frac{ v _{f}+v _{i} }{ 2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0conservation is so much easier to solve

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0it confused me though the first equstion

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Don't worry about it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@omnomnom This is a two step problem. First you want to figure out how long it took to fall. Then you want to use that to figure out how far it fell.

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay so what equation do i use.... is is\[d =Vi( t)+ a \frac{ 1 }{ 2 }(t^2) \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You can't use that equation until you find time though.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[a=\frac{ v _{f}v _{i} }{ t }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you know a and both velocities

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0But we need the time :( Cant i just quess the answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, \(a\) is the same as last time... \(9.81m/s^2\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0velocity initial is 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You are not supposed to guess, because there is already a way to find the answer.

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0but...... Whats the way ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then plug in the time into your equation and find x

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0so we change the equation now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you want the height of the building

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x=1/2t(vfinalvinital)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you understand the kinematic equations

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0The first one ? NO the others Yes

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is a helpfull tool
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