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motza11

  • 3 years ago

Anyone know how to solve this differential equation? sin(x+y)dy=dx

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  1. motza11
    • 3 years ago
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    How do I solve this differential equation?

  2. cinar
    • 3 years ago
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    v=x+y v'=1+y' y'-cosec(x+y)=0 v'-1-cosecv=0 v'=1+cosecv dv/(1+cosecv)=dx

  3. cinar
    • 3 years ago
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    sinv/(1+sinv)*dv=dx take integral

  4. motza11
    • 3 years ago
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    Ok, let me chew on this for a bit... thanks!

  5. cinar
    • 3 years ago
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    np..

  6. motza11
    • 3 years ago
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    so... 1/(1+cosec v) = sin v / (1 + sin v) ?

  7. motza11
    • 3 years ago
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    is this an identity that I should know?

  8. cinar
    • 3 years ago
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    cosecx=1/sinx

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