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How do I solve this differential equation?

v=x+y
v'=1+y'
y'-cosec(x+y)=0
v'-1-cosecv=0
v'=1+cosecv
dv/(1+cosecv)=dx

sinv/(1+sinv)*dv=dx take integral

Ok, let me chew on this for a bit... thanks!

np..

so... 1/(1+cosec v) = sin v / (1 + sin v) ?

is this an identity that I should know?

cosecx=1/sinx