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Anyone know how to solve this differential equation? sin(x+y)dy=dx

Mathematics
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How do I solve this differential equation?
v=x+y v'=1+y' y'-cosec(x+y)=0 v'-1-cosecv=0 v'=1+cosecv dv/(1+cosecv)=dx
sinv/(1+sinv)*dv=dx take integral

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Other answers:

Ok, let me chew on this for a bit... thanks!
np..
so... 1/(1+cosec v) = sin v / (1 + sin v) ?
is this an identity that I should know?
cosecx=1/sinx

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