motza11
Anyone know how to solve this differential equation?
sin(x+y)dy=dx



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motza11
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How do I solve this differential equation?

cinar
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v=x+y
v'=1+y'
y'cosec(x+y)=0
v'1cosecv=0
v'=1+cosecv
dv/(1+cosecv)=dx

cinar
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sinv/(1+sinv)*dv=dx take integral

motza11
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Ok, let me chew on this for a bit... thanks!

cinar
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np..

motza11
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so... 1/(1+cosec v) = sin v / (1 + sin v) ?

motza11
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is this an identity that I should know?

cinar
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cosecx=1/sinx