A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Open

Yoloswag097
 2 years ago
Best ResponseYou've already chosen the best response.01(sin 2 theta) / (1cos theta) = cos theta

cinar
 2 years ago
Best ResponseYou've already chosen the best response.01+cosx=sin2x/(1cosx) 1(cosx)^2=2sinxcosx (sinx)^2=2sinxcosx sinx=2cosx tanx=2 x=arctan2 x=63.43 degree or 1.107 radians

2le
 2 years ago
Best ResponseYou've already chosen the best response.1\[1  \frac{sin(2\theta)}{1cos(\theta)} = cos(\theta)\] \[1 +cos(\theta) = \frac{sin(2\theta)}{1cos(\theta)}\] \[(1 +cos(\theta))(1cos(\theta)) = \frac{sin(2\theta)}{1cos(\theta)}*(1cos(\theta))\] \[1 cos^2(\theta) = sin(2\theta)\] note that \[1 = sin^2(\theta) + cos^2(\theta) \] therefore \[1 cos^2(\theta) = sin^2(\theta)\] so plug that back into the orginal equation \[sin^2(\theta) = sin(2\theta)\] also note that \[2cos(\theta)sin(\theta) = sin(2\theta)\] therefore \[sin^2(\theta) = 2cos(\theta)sin(\theta)\] divide by \[sin(\theta)\] and you get \[sin(\theta)=2cos(\theta)\] divide by \[cos(\theta)\]and you get \[tan(\theta)=2\] do a little \[tan^{1}(\theta)=tan^{1}(2)\] and you've solved for theta
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.