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anonymous
 3 years ago
differentiate
ln(7e^x+xe^x)
anonymous
 3 years ago
differentiate ln(7e^x+xe^x)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my answer was 1/f(x) * f'(x). but it keeps saying wrong

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3first take e^(x) common from (7e^x+xe^x) then use the property of log. log ab=log a + log b

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer=(7e^x+e^xxe^x)/(7e^x+xe^x)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3ln [e^x(7+x)] now use log ab = log a +log b

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, lne^x+ln(7+x), and go from there?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3u can simplify ln(e^(x)) do u know how ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, im afraid not goku. :l

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3\(\huge ln e^{(a)}=aln e=a\) now ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, x+ln(7+x)? is that right so far?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3yes, that is correct :) now its differentiation is simple....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01+...ermm 1/(7+x)*1?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3that is absolutely correct (except for ...ermm part) simplify it further

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol, wow. thank you goku san.
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