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steel11Best ResponseYou've already chosen the best response.0
my answer was 1/f(x) * f'(x). but it keeps saying wrong
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
first take e^(x) common from (7e^x+xe^x) then use the property of log. log ab=log a + log b
 one year ago

cinarBest ResponseYou've already chosen the best response.0
answer=(7e^x+e^xxe^x)/(7e^x+xe^x)
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
ln [e^x(7+x)] now use log ab = log a +log b
 one year ago

steel11Best ResponseYou've already chosen the best response.0
so, lne^x+ln(7+x), and go from there?
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
u can simplify ln(e^(x)) do u know how ?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
no, im afraid not goku. :l
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
\(\huge ln e^{(a)}=aln e=a\) now ?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
so, x+ln(7+x)? is that right so far?
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
yes, that is correct :) now its differentiation is simple....
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
that is absolutely correct (except for ...ermm part) simplify it further
 one year ago

steel11Best ResponseYou've already chosen the best response.0
lol, wow. thank you goku san.
 one year ago
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