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 2 years ago
Can someone help me with this. A mixture of 30 lbs. of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of each kind were used to make the mixture? ___ lbs. of $1.50 chocolates and ____ lbs. of 90¢ chocolate
 2 years ago
Can someone help me with this. A mixture of 30 lbs. of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of each kind were used to make the mixture? ___ lbs. of $1.50 chocolates and ____ lbs. of 90¢ chocolate

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CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0I think a system of two linear equations will take care of it. Do you have experience with that method of solving?

Claire4christ
 2 years ago
Best ResponseYou've already chosen the best response.0mixed problem right

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0You'll need to develop at least two equations to represent the information that you are given. e.g. if there are 30lbs. total, then x+y=30, x = pounds of $1.50 chocolates, y = $0.90 chocolates. Can you come up with another equation?

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0(Hint: what is the total cost of that 30lbs. of candy?)

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Make sure your units match up. If you're using 15 and 9, those are in units of dimes, The 30 is in units of pounds. You can't add groups of dimes together to make a number of pounds. They are not the same kind of thing.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Ok, so you have x pounds at $1.10 + y pounds at $0.90 and together they add up to $33.00. You now have two equations with which to solve for your two unknowns.
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