anonymous
  • anonymous
if cos 0<0 and tan 0 >0 then in which quadrant does 0 lie? (0=beta IDK how to do the symbol on here)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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hartnn
  • hartnn
|dw:1349413466539:dw| the ratios mentioned are positive in that quadrant.
anonymous
  • anonymous
oh so its in quadrant 1?
hartnn
  • hartnn
in quadrant 1 ALL are positive, your question requires, tan to be negaive, so its not in 1st quadrant

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hartnn
  • hartnn
*sorry, cos to be negative
hartnn
  • hartnn
from the diagram, in which quadrant you find tan to be positive ?
anonymous
  • anonymous
oh so 4?
hartnn
  • hartnn
|dw:1349413799469:dw|
anonymous
  • anonymous
uh tan is positive in idk i looking at my unit circle and where tan is on your diagram its negative unless its in q1
anonymous
  • anonymous
cos (beta) < 0 means beta is in QII, QIII tan (beta) > 0 means beta is in QIII, QI where does beta have to be to meet these two requirements?
hartnn
  • hartnn
|dw:1349413873008:dw|
anonymous
  • anonymous
but tan is x right? wait can i even reate this to this|dw:1349413939970:dw|
hartnn
  • hartnn
that circle has co=ordinates of cos and sine so now you know the signs of cos and sine can u find out sign of tan using that, in each quadrant ?
anonymous
  • anonymous
oh wait tan = sin/cos/45 in which yes that part is positive so its in q3!!!!!
anonymous
  • anonymous
hey just for note taking is the cot negative then?
hartnn
  • hartnn
when tan is positive cot = 1/ tan is also positive
anonymous
  • anonymous
so is tan ever negative then cat is too
hartnn
  • hartnn
tan is negative when only one of sin or cos is negative, that is in 2nd and 4th quadrant
anonymous
  • anonymous
and in the all part they're alll only positive right
hartnn
  • hartnn
yes. in 1st quadrant all ratios are positive
anonymous
  • anonymous
just a way, i used to remember above diagaram, Add , Sugar, To ,Coffe...
anonymous
  • anonymous
okay then in q2 and q4 then cot is - yes?
hartnn
  • hartnn
yes.
anonymous
  • anonymous
okay then sin is + in q2 and - in q 3 and 4?
hartnn
  • hartnn
yes, you are reading it correctly :)
anonymous
  • anonymous
okay then what about sec
anonymous
  • anonymous
to akash_809 I see wat you did there
hartnn
  • hartnn
since sec = 1/cos sign of sec is same as sign of cos everywhere
anonymous
  • anonymous
oh i meant csc
hartnn
  • hartnn
csc x =1/ sin x sign of csc is same as sign of sin everywhere
anonymous
  • anonymous
oh wait cos is + in q4 and - in q 2 and 3 correct?
hartnn
  • hartnn
yes.
anonymous
  • anonymous
okay now can we do the next question
hartnn
  • hartnn
u can use Add sugar to coffee or All silver tea cups to remember that diagram. or you could make one on your own.
hartnn
  • hartnn
like add sugarrainbow to castle
anonymous
  • anonymous
lol
anonymous
  • anonymous
yeah i gots it now the all suckers take crap is the ones that are the only ones positive in their quadrant (except q1 where they're all positive)
anonymous
  • anonymous
okay next question how would you find exact value of 5pi/3?
hartnn
  • hartnn
5pi/3 ? in degrees ? or some ratio of 5pi/3 ? like sin 5pi/3
anonymous
  • anonymous
umm it just says "the exact value of csc (5pi/3) (oops i guess i forgot the ratio part sorry)
hartnn
  • hartnn
u need to use some of trignometry identities. first can u find sin (5pi/3) because csc =1/ sin
anonymous
  • anonymous
i need help . The image below shows two parallel lines cut by a transversal. What is the value of a? two vertical lines cut with a transversal, the angle below and to the right of where the transversal intersects the left line is labeled 2 a plus 3 degrees, and the angle above and to the right of where the transversal intersects the right line is labeled a degrees
anonymous
  • anonymous
yes its -square root 3/2 and you would multiply by radical 3 to get -2sqrt3/3!!!!
hartnn
  • hartnn
umm, - root 3 / 2 ... why do u need to multiply by radical ? sin 5pi/6 = - root 3 /2 csc 5 pi/6 = -2/ root 3 here, you will multiply by radical 3 to get csc 5pi/6 = -2sqrt3/3
anonymous
  • anonymous
yeah that's what i got?
hartnn
  • hartnn
then you are correct :)
anonymous
  • anonymous
okay last question how would you horizontally shift y=4 sin (beta-80)
anonymous
  • anonymous
oh yeah and this question says determine the exact values of the 6 trigonometric functios of an angle in standard position whose terminal side passes through the point (-1,3) and for tan i got -1/3 and cot i got 3/3 and she said its wrong so was i supposed to do...
anonymous
  • anonymous
-1/sqrt10 then multiply by sqrt 10 to get -1sqrt10/10?
hartnn
  • hartnn
sorry, can u post this as a new question, i need to go :(

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