At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
|dw:1349413466539:dw| the ratios mentioned are positive in that quadrant.
oh so its in quadrant 1?
in quadrant 1 ALL are positive, your question requires, tan to be negaive, so its not in 1st quadrant
*sorry, cos to be negative
from the diagram, in which quadrant you find tan to be positive ?
oh so 4?
uh tan is positive in idk i looking at my unit circle and where tan is on your diagram its negative unless its in q1
cos (beta) < 0 means beta is in QII, QIII tan (beta) > 0 means beta is in QIII, QI where does beta have to be to meet these two requirements?
but tan is x right? wait can i even reate this to this|dw:1349413939970:dw|
that circle has co=ordinates of cos and sine so now you know the signs of cos and sine can u find out sign of tan using that, in each quadrant ?
oh wait tan = sin/cos/45 in which yes that part is positive so its in q3!!!!!
hey just for note taking is the cot negative then?
when tan is positive cot = 1/ tan is also positive
so is tan ever negative then cat is too
tan is negative when only one of sin or cos is negative, that is in 2nd and 4th quadrant
and in the all part they're alll only positive right
yes. in 1st quadrant all ratios are positive
just a way, i used to remember above diagaram, Add , Sugar, To ,Coffe...
okay then in q2 and q4 then cot is - yes?
okay then sin is + in q2 and - in q 3 and 4?
yes, you are reading it correctly :)
okay then what about sec
to akash_809 I see wat you did there
since sec = 1/cos sign of sec is same as sign of cos everywhere
oh i meant csc
csc x =1/ sin x sign of csc is same as sign of sin everywhere
oh wait cos is + in q4 and - in q 2 and 3 correct?
okay now can we do the next question
u can use Add sugar to coffee or All silver tea cups to remember that diagram. or you could make one on your own.
like add sugarrainbow to castle
yeah i gots it now the all suckers take crap is the ones that are the only ones positive in their quadrant (except q1 where they're all positive)
okay next question how would you find exact value of 5pi/3?
5pi/3 ? in degrees ? or some ratio of 5pi/3 ? like sin 5pi/3
umm it just says "the exact value of csc (5pi/3) (oops i guess i forgot the ratio part sorry)
u need to use some of trignometry identities. first can u find sin (5pi/3) because csc =1/ sin
i need help . The image below shows two parallel lines cut by a transversal. What is the value of a? two vertical lines cut with a transversal, the angle below and to the right of where the transversal intersects the left line is labeled 2 a plus 3 degrees, and the angle above and to the right of where the transversal intersects the right line is labeled a degrees
yes its -square root 3/2 and you would multiply by radical 3 to get -2sqrt3/3!!!!
umm, - root 3 / 2 ... why do u need to multiply by radical ? sin 5pi/6 = - root 3 /2 csc 5 pi/6 = -2/ root 3 here, you will multiply by radical 3 to get csc 5pi/6 = -2sqrt3/3
yeah that's what i got?
then you are correct :)
okay last question how would you horizontally shift y=4 sin (beta-80)
oh yeah and this question says determine the exact values of the 6 trigonometric functios of an angle in standard position whose terminal side passes through the point (-1,3) and for tan i got -1/3 and cot i got 3/3 and she said its wrong so was i supposed to do...
-1/sqrt10 then multiply by sqrt 10 to get -1sqrt10/10?
sorry, can u post this as a new question, i need to go :(