if cos 0<0 and tan 0 >0 then in which quadrant does 0 lie?
(0=beta IDK how to do the symbol on here)

- anonymous

if cos 0<0 and tan 0 >0 then in which quadrant does 0 lie?
(0=beta IDK how to do the symbol on here)

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- hartnn

|dw:1349413466539:dw|
the ratios mentioned are positive in that quadrant.

- anonymous

oh so its in quadrant 1?

- hartnn

in quadrant 1 ALL are positive, your question requires, tan to be negaive, so its not in 1st quadrant

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## More answers

- hartnn

*sorry, cos to be negative

- hartnn

from the diagram, in which quadrant you find tan to be positive ?

- anonymous

oh so 4?

- hartnn

|dw:1349413799469:dw|

- anonymous

uh tan is positive in idk i looking at my unit circle and where tan is on your diagram its negative unless its in q1

- anonymous

cos (beta) < 0 means beta is in QII, QIII
tan (beta) > 0 means beta is in QIII, QI
where does beta have to be to meet these two requirements?

- hartnn

|dw:1349413873008:dw|

- anonymous

but tan is x right? wait can i even reate this to this|dw:1349413939970:dw|

- hartnn

that circle has co=ordinates of cos and sine
so now you know the signs of cos and sine
can u find out sign of tan using that, in each quadrant ?

- anonymous

oh wait tan = sin/cos/45 in which yes that part is positive so its in q3!!!!!

- anonymous

hey just for note taking is the cot negative then?

- hartnn

when tan is positive cot = 1/ tan is also positive

- anonymous

so is tan ever negative then cat is too

- hartnn

tan is negative when only one of sin or cos is negative, that is in 2nd and 4th quadrant

- anonymous

and in the all part they're alll only positive right

- hartnn

yes. in 1st quadrant all ratios are positive

- anonymous

just a way, i used to remember above diagaram, Add , Sugar, To ,Coffe...

- anonymous

okay then in q2 and q4 then cot is - yes?

- hartnn

yes.

- anonymous

okay then sin is + in q2 and - in q 3 and 4?

- hartnn

yes, you are reading it correctly :)

- anonymous

okay then what about sec

- anonymous

to akash_809 I see wat you did there

- hartnn

since sec = 1/cos
sign of sec is same as sign of cos everywhere

- anonymous

oh i meant csc

- hartnn

csc x =1/ sin x
sign of csc is same as sign of sin everywhere

- anonymous

oh wait cos is + in q4 and - in q 2 and 3 correct?

- hartnn

yes.

- anonymous

okay now can we do the next question

- hartnn

u can use Add sugar to coffee or All silver tea cups to remember that diagram.
or you could make one on your own.

- hartnn

like add sugarrainbow to castle

- anonymous

lol

- anonymous

yeah i gots it now the all suckers take crap is the ones that are the only ones positive in their quadrant (except q1 where they're all positive)

- anonymous

okay next question how would you find exact value of 5pi/3?

- hartnn

5pi/3 ? in degrees ?
or some ratio of 5pi/3 ? like sin 5pi/3

- anonymous

umm it just says "the exact value of csc (5pi/3)
(oops i guess i forgot the ratio part sorry)

- hartnn

u need to use some of trignometry identities.
first can u find sin (5pi/3)
because csc =1/ sin

- anonymous

i need help .
The image below shows two parallel lines cut by a transversal. What is the value of a?
two vertical lines cut with a transversal, the angle below and to the right of where the transversal intersects the left line is labeled 2 a plus 3 degrees, and the angle above and to the right of where the transversal intersects the right line is labeled a degrees

- anonymous

yes its -square root 3/2 and you would multiply by radical 3 to get -2sqrt3/3!!!!

- hartnn

umm, - root 3 / 2 ... why do u need to multiply by radical ?
sin 5pi/6 = - root 3 /2
csc 5 pi/6 = -2/ root 3
here, you will multiply by radical 3 to get
csc 5pi/6 = -2sqrt3/3

- anonymous

yeah that's what i got?

- hartnn

then you are correct :)

- anonymous

okay last question how would you horizontally shift y=4 sin (beta-80)

- anonymous

oh yeah and this question says determine the exact values of the 6 trigonometric functios of an angle in standard position whose terminal side passes through the point (-1,3) and for tan i got -1/3 and cot i got 3/3 and she said its wrong so was i supposed to do...

- anonymous

-1/sqrt10 then multiply by sqrt 10 to get -1sqrt10/10?

- hartnn

sorry, can u post this as a new question, i need to go :(

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