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|dw:1349413466539:dw|
the ratios mentioned are positive in that quadrant.

oh so its in quadrant 1?

*sorry, cos to be negative

from the diagram, in which quadrant you find tan to be positive ?

oh so 4?

|dw:1349413799469:dw|

|dw:1349413873008:dw|

but tan is x right? wait can i even reate this to this|dw:1349413939970:dw|

oh wait tan = sin/cos/45 in which yes that part is positive so its in q3!!!!!

hey just for note taking is the cot negative then?

when tan is positive cot = 1/ tan is also positive

so is tan ever negative then cat is too

tan is negative when only one of sin or cos is negative, that is in 2nd and 4th quadrant

and in the all part they're alll only positive right

yes. in 1st quadrant all ratios are positive

just a way, i used to remember above diagaram, Add , Sugar, To ,Coffe...

okay then in q2 and q4 then cot is - yes?

yes.

okay then sin is + in q2 and - in q 3 and 4?

yes, you are reading it correctly :)

okay then what about sec

to akash_809 I see wat you did there

since sec = 1/cos
sign of sec is same as sign of cos everywhere

oh i meant csc

csc x =1/ sin x
sign of csc is same as sign of sin everywhere

oh wait cos is + in q4 and - in q 2 and 3 correct?

yes.

okay now can we do the next question

like add sugarrainbow to castle

lol

okay next question how would you find exact value of 5pi/3?

5pi/3 ? in degrees ?
or some ratio of 5pi/3 ? like sin 5pi/3

umm it just says "the exact value of csc (5pi/3)
(oops i guess i forgot the ratio part sorry)

u need to use some of trignometry identities.
first can u find sin (5pi/3)
because csc =1/ sin

yes its -square root 3/2 and you would multiply by radical 3 to get -2sqrt3/3!!!!

yeah that's what i got?

then you are correct :)

okay last question how would you horizontally shift y=4 sin (beta-80)

-1/sqrt10 then multiply by sqrt 10 to get -1sqrt10/10?

sorry, can u post this as a new question, i need to go :(