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SugarRainbow

  • 3 years ago

if cos 0<0 and tan 0 >0 then in which quadrant does 0 lie? (0=beta IDK how to do the symbol on here)

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  1. hartnn
    • 3 years ago
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    |dw:1349413466539:dw| the ratios mentioned are positive in that quadrant.

  2. SugarRainbow
    • 3 years ago
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    oh so its in quadrant 1?

  3. hartnn
    • 3 years ago
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    in quadrant 1 ALL are positive, your question requires, tan to be negaive, so its not in 1st quadrant

  4. hartnn
    • 3 years ago
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    *sorry, cos to be negative

  5. hartnn
    • 3 years ago
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    from the diagram, in which quadrant you find tan to be positive ?

  6. SugarRainbow
    • 3 years ago
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    oh so 4?

  7. hartnn
    • 3 years ago
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    |dw:1349413799469:dw|

  8. SugarRainbow
    • 3 years ago
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    uh tan is positive in idk i looking at my unit circle and where tan is on your diagram its negative unless its in q1

  9. ByteMe
    • 3 years ago
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    cos (beta) < 0 means beta is in QII, QIII tan (beta) > 0 means beta is in QIII, QI where does beta have to be to meet these two requirements?

  10. hartnn
    • 3 years ago
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    |dw:1349413873008:dw|

  11. SugarRainbow
    • 3 years ago
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    but tan is x right? wait can i even reate this to this|dw:1349413939970:dw|

  12. hartnn
    • 3 years ago
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    that circle has co=ordinates of cos and sine so now you know the signs of cos and sine can u find out sign of tan using that, in each quadrant ?

  13. SugarRainbow
    • 3 years ago
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    oh wait tan = sin/cos/45 in which yes that part is positive so its in q3!!!!!

  14. SugarRainbow
    • 3 years ago
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    hey just for note taking is the cot negative then?

  15. hartnn
    • 3 years ago
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    when tan is positive cot = 1/ tan is also positive

  16. SugarRainbow
    • 3 years ago
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    so is tan ever negative then cat is too

  17. hartnn
    • 3 years ago
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    tan is negative when only one of sin or cos is negative, that is in 2nd and 4th quadrant

  18. SugarRainbow
    • 3 years ago
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    and in the all part they're alll only positive right

  19. hartnn
    • 3 years ago
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    yes. in 1st quadrant all ratios are positive

  20. akash_809
    • 3 years ago
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    just a way, i used to remember above diagaram, Add , Sugar, To ,Coffe...

  21. SugarRainbow
    • 3 years ago
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    okay then in q2 and q4 then cot is - yes?

  22. hartnn
    • 3 years ago
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    yes.

  23. SugarRainbow
    • 3 years ago
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    okay then sin is + in q2 and - in q 3 and 4?

  24. hartnn
    • 3 years ago
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    yes, you are reading it correctly :)

  25. SugarRainbow
    • 3 years ago
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    okay then what about sec

  26. SugarRainbow
    • 3 years ago
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    to akash_809 I see wat you did there

  27. hartnn
    • 3 years ago
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    since sec = 1/cos sign of sec is same as sign of cos everywhere

  28. SugarRainbow
    • 3 years ago
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    oh i meant csc

  29. hartnn
    • 3 years ago
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    csc x =1/ sin x sign of csc is same as sign of sin everywhere

  30. SugarRainbow
    • 3 years ago
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    oh wait cos is + in q4 and - in q 2 and 3 correct?

  31. hartnn
    • 3 years ago
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    yes.

  32. SugarRainbow
    • 3 years ago
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    okay now can we do the next question

  33. hartnn
    • 3 years ago
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    u can use Add sugar to coffee or All silver tea cups to remember that diagram. or you could make one on your own.

  34. hartnn
    • 3 years ago
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    like add sugarrainbow to castle

  35. SugarRainbow
    • 3 years ago
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    lol

  36. SugarRainbow
    • 3 years ago
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    yeah i gots it now the all suckers take crap is the ones that are the only ones positive in their quadrant (except q1 where they're all positive)

  37. SugarRainbow
    • 3 years ago
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    okay next question how would you find exact value of 5pi/3?

  38. hartnn
    • 3 years ago
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    5pi/3 ? in degrees ? or some ratio of 5pi/3 ? like sin 5pi/3

  39. SugarRainbow
    • 3 years ago
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    umm it just says "the exact value of csc (5pi/3) (oops i guess i forgot the ratio part sorry)

  40. hartnn
    • 3 years ago
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    u need to use some of trignometry identities. first can u find sin (5pi/3) because csc =1/ sin

  41. cansdy21356
    • 3 years ago
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    i need help . The image below shows two parallel lines cut by a transversal. What is the value of a? two vertical lines cut with a transversal, the angle below and to the right of where the transversal intersects the left line is labeled 2 a plus 3 degrees, and the angle above and to the right of where the transversal intersects the right line is labeled a degrees

  42. SugarRainbow
    • 3 years ago
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    yes its -square root 3/2 and you would multiply by radical 3 to get -2sqrt3/3!!!!

  43. hartnn
    • 3 years ago
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    umm, - root 3 / 2 ... why do u need to multiply by radical ? sin 5pi/6 = - root 3 /2 csc 5 pi/6 = -2/ root 3 here, you will multiply by radical 3 to get csc 5pi/6 = -2sqrt3/3

  44. SugarRainbow
    • 3 years ago
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    yeah that's what i got?

  45. hartnn
    • 3 years ago
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    then you are correct :)

  46. SugarRainbow
    • 3 years ago
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    okay last question how would you horizontally shift y=4 sin (beta-80)

  47. SugarRainbow
    • 3 years ago
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    oh yeah and this question says determine the exact values of the 6 trigonometric functios of an angle in standard position whose terminal side passes through the point (-1,3) and for tan i got -1/3 and cot i got 3/3 and she said its wrong so was i supposed to do...

  48. SugarRainbow
    • 3 years ago
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    -1/sqrt10 then multiply by sqrt 10 to get -1sqrt10/10?

  49. hartnn
    • 3 years ago
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    sorry, can u post this as a new question, i need to go :(

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