if cos 0<0 and tan 0 >0 then in which quadrant does 0 lie?
(0=beta IDK how to do the symbol on here)

- anonymous

if cos 0<0 and tan 0 >0 then in which quadrant does 0 lie?
(0=beta IDK how to do the symbol on here)

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- hartnn

|dw:1349413466539:dw|
the ratios mentioned are positive in that quadrant.

- anonymous

oh so its in quadrant 1?

- hartnn

in quadrant 1 ALL are positive, your question requires, tan to be negaive, so its not in 1st quadrant

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- hartnn

*sorry, cos to be negative

- hartnn

from the diagram, in which quadrant you find tan to be positive ?

- anonymous

oh so 4?

- hartnn

|dw:1349413799469:dw|

- anonymous

uh tan is positive in idk i looking at my unit circle and where tan is on your diagram its negative unless its in q1

- anonymous

cos (beta) < 0 means beta is in QII, QIII
tan (beta) > 0 means beta is in QIII, QI
where does beta have to be to meet these two requirements?

- hartnn

|dw:1349413873008:dw|

- anonymous

but tan is x right? wait can i even reate this to this|dw:1349413939970:dw|

- hartnn

that circle has co=ordinates of cos and sine
so now you know the signs of cos and sine
can u find out sign of tan using that, in each quadrant ?

- anonymous

oh wait tan = sin/cos/45 in which yes that part is positive so its in q3!!!!!

- anonymous

hey just for note taking is the cot negative then?

- hartnn

when tan is positive cot = 1/ tan is also positive

- anonymous

so is tan ever negative then cat is too

- hartnn

tan is negative when only one of sin or cos is negative, that is in 2nd and 4th quadrant

- anonymous

and in the all part they're alll only positive right

- hartnn

yes. in 1st quadrant all ratios are positive

- anonymous

just a way, i used to remember above diagaram, Add , Sugar, To ,Coffe...

- anonymous

okay then in q2 and q4 then cot is - yes?

- hartnn

yes.

- anonymous

okay then sin is + in q2 and - in q 3 and 4?

- hartnn

yes, you are reading it correctly :)

- anonymous

okay then what about sec

- anonymous

to akash_809 I see wat you did there

- hartnn

since sec = 1/cos
sign of sec is same as sign of cos everywhere

- anonymous

oh i meant csc

- hartnn

csc x =1/ sin x
sign of csc is same as sign of sin everywhere

- anonymous

oh wait cos is + in q4 and - in q 2 and 3 correct?

- hartnn

yes.

- anonymous

okay now can we do the next question

- hartnn

u can use Add sugar to coffee or All silver tea cups to remember that diagram.
or you could make one on your own.

- hartnn

like add sugarrainbow to castle

- anonymous

lol

- anonymous

yeah i gots it now the all suckers take crap is the ones that are the only ones positive in their quadrant (except q1 where they're all positive)

- anonymous

okay next question how would you find exact value of 5pi/3?

- hartnn

5pi/3 ? in degrees ?
or some ratio of 5pi/3 ? like sin 5pi/3

- anonymous

umm it just says "the exact value of csc (5pi/3)
(oops i guess i forgot the ratio part sorry)

- hartnn

u need to use some of trignometry identities.
first can u find sin (5pi/3)
because csc =1/ sin

- anonymous

i need help .
The image below shows two parallel lines cut by a transversal. What is the value of a?
two vertical lines cut with a transversal, the angle below and to the right of where the transversal intersects the left line is labeled 2 a plus 3 degrees, and the angle above and to the right of where the transversal intersects the right line is labeled a degrees

- anonymous

yes its -square root 3/2 and you would multiply by radical 3 to get -2sqrt3/3!!!!

- hartnn

umm, - root 3 / 2 ... why do u need to multiply by radical ?
sin 5pi/6 = - root 3 /2
csc 5 pi/6 = -2/ root 3
here, you will multiply by radical 3 to get
csc 5pi/6 = -2sqrt3/3

- anonymous

yeah that's what i got?

- hartnn

then you are correct :)

- anonymous

okay last question how would you horizontally shift y=4 sin (beta-80)

- anonymous

oh yeah and this question says determine the exact values of the 6 trigonometric functios of an angle in standard position whose terminal side passes through the point (-1,3) and for tan i got -1/3 and cot i got 3/3 and she said its wrong so was i supposed to do...

- anonymous

-1/sqrt10 then multiply by sqrt 10 to get -1sqrt10/10?

- hartnn

sorry, can u post this as a new question, i need to go :(

Looking for something else?

Not the answer you are looking for? Search for more explanations.