Calculating elongation of the spring Consider a spring of spring constant 100 N/m.. it is suspended vertically and a block of 1kg is attached to it.. calculate the elongation of the spring from the equilibrium position.

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I did it in two methods and i get different answers.. a) using net force at equilibrum is zero at the final position the net force is zero. and there are two forces acting hence -kx + mg = 0 so x =mg/k ----- (1) b) Considering energy conservation Total Energy before = Total energy after T.E before = PEg = mgh (Say h is the height above the ground just when block released) T.E after = PEg + PEspring = mg (h-x) + 1/2 Kx^2 mgh = mgh - mgx +!/2 kx^2 mgx = 1/2kx^2 mg = 1/2kx x = 2mg/k see i get double the answer :(!!

In b), you were finding x at the lowest point if the spring is released from some height. In a) x is elongation when the block reach equilibrium, not oscillating anymore.

Ohhhhhh.. stupid .. stupid I AM!!!!!.. HTANK YOU!!!!

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