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lgbasallote

  • 2 years ago

if P(A) = 0.75 and P(B = 0.8) and P(A' \(\cap\) B') = 0.05 are events A and B independent?

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  1. calculusfunctions
    • 2 years ago
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    Two events A and B are independent events iff P(A and B) = P(A) x P(B).

  2. lgbasallote
    • 2 years ago
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    hmmm

  3. lgbasallote
    • 2 years ago
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    that's not dependent?

  4. calculusfunctions
    • 2 years ago
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    Nope!

  5. calculusfunctions
    • 2 years ago
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    In your question, P(not A) = 0.25 and the P(not B) = 0.2 and P(not A and not B) = 0.95. P(not A) x P(not B) = 0.25 x 0.2 = 0.05 = P(not A and not B) ∴ A and B are independent events.

  6. lgbasallote
    • 2 years ago
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    i thought B was independent if P(A|B) = P(A'|B)

  7. lgbasallote
    • 2 years ago
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    nevermind. i got it

  8. calculusfunctions
    • 2 years ago
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    Oh my gosh! There is something majorly wrong with my computer. I was almost finished with the explanation and it froze. I'll start over. Give me a few minutes.

  9. calculusfunctions
    • 2 years ago
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    OK good so I don't have to start over. You see that my explanation was right.

  10. lgbasallote
    • 2 years ago
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    yes except for a minor typographical error but understandable

  11. calculusfunctions
    • 2 years ago
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    Good! Let me know if you change your mind and want to see the explanation.

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spraguer (Moderator)
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