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shivraj

  • 2 years ago

9xy^3/18x^5 y^8?

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  1. radh
    • 2 years ago
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    Do you see a common factor in the coefficients?

  2. shivraj
    • 2 years ago
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    ya

  3. radh
    • 2 years ago
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    Divide that, what do you get?

  4. radh
    • 2 years ago
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    Are you there @shivraj?

  5. shivraj
    • 2 years ago
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    yep

  6. shivraj
    • 2 years ago
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    9/(2*9) 1/2

  7. radh
    • 2 years ago
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    so what would that be in the whole context of the equation?

  8. shivraj
    • 2 years ago
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    1/2x^-4y^-5

  9. radh
    • 2 years ago
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    oh wait wait, where'd we get that negative? it should be 1/(2x^4y^5)

  10. shivraj
    • 2 years ago
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    1/(2x^4y^5)

  11. radh
    • 2 years ago
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    yeah. that's now your final answer, because there's nothing else to divide by. do you understand it?

  12. radh
    • 2 years ago
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    so look at the coefficients first, unless you can factor it out. (but that's a totally different problem we don't need to worry about right now)

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