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shivraj Group Title

9xy^3/18x^5 y^8?

  • one year ago
  • one year ago

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  1. radh Group Title
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    Do you see a common factor in the coefficients?

    • one year ago
  2. shivraj Group Title
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    ya

    • one year ago
  3. radh Group Title
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    Divide that, what do you get?

    • one year ago
  4. radh Group Title
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    Are you there @shivraj?

    • one year ago
  5. shivraj Group Title
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    yep

    • one year ago
  6. shivraj Group Title
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    9/(2*9) 1/2

    • one year ago
  7. radh Group Title
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    so what would that be in the whole context of the equation?

    • one year ago
  8. shivraj Group Title
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    1/2x^-4y^-5

    • one year ago
  9. radh Group Title
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    oh wait wait, where'd we get that negative? it should be 1/(2x^4y^5)

    • one year ago
  10. shivraj Group Title
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    1/(2x^4y^5)

    • one year ago
  11. radh Group Title
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    yeah. that's now your final answer, because there's nothing else to divide by. do you understand it?

    • one year ago
  12. radh Group Title
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    so look at the coefficients first, unless you can factor it out. (but that's a totally different problem we don't need to worry about right now)

    • one year ago
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