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9xy^3/18x^5 y^8?

Mathematics
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Do you see a common factor in the coefficients?
ya
Divide that, what do you get?

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Other answers:

Are you there @shivraj?
yep
9/(2*9) 1/2
so what would that be in the whole context of the equation?
1/2x^-4y^-5
oh wait wait, where'd we get that negative? it should be 1/(2x^4y^5)
1/(2x^4y^5)
yeah. that's now your final answer, because there's nothing else to divide by. do you understand it?
so look at the coefficients first, unless you can factor it out. (but that's a totally different problem we don't need to worry about right now)

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