9xy^3/18x^5 y^8?

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9xy^3/18x^5 y^8?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Do you see a common factor in the coefficients?
ya
Divide that, what do you get?

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Other answers:

Are you there @shivraj?
yep
9/(2*9) 1/2
so what would that be in the whole context of the equation?
1/2x^-4y^-5
oh wait wait, where'd we get that negative? it should be 1/(2x^4y^5)
1/(2x^4y^5)
yeah. that's now your final answer, because there's nothing else to divide by. do you understand it?
so look at the coefficients first, unless you can factor it out. (but that's a totally different problem we don't need to worry about right now)

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