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A college plays 12 football games during a season. In how many ways can the team end the season with 7 win, 3 losses and 2 ties?

Mathematics
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i think its 12!/(7!3!2!)
no idea what it is @sauravshakya
but how did you get those numbers @sauravshakya and @hartnn

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Other answers:

It is 12C7*(12-7)C3 = 12C7*5C3=7920
Same as @hartnn got.
i wonder when someone wll actually explain something....
Its like choosing 7 teams from the 12 teams against which we win.... and from the remaining 5 teams we choose 3 teams against which we lose and from the remaining 2 teams we choose two teams against which we play tie.
teamSSSS? isn't there only one team?
Same thing: Replace teams with games
yes. that does make sense

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