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lgbasallote

  • 3 years ago

A college plays 12 football games during a season. In how many ways can the team end the season with 7 win, 3 losses and 2 ties?

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  1. hartnn
    • 3 years ago
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    i think its 12!/(7!3!2!)

  2. lgbasallote
    • 3 years ago
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    no idea what it is @sauravshakya

  3. lgbasallote
    • 3 years ago
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    but how did you get those numbers @sauravshakya and @hartnn

  4. sauravshakya
    • 3 years ago
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    It is 12C7*(12-7)C3 = 12C7*5C3=7920

  5. sauravshakya
    • 3 years ago
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    Same as @hartnn got.

  6. lgbasallote
    • 3 years ago
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    i wonder when someone wll actually explain something....

  7. sauravshakya
    • 3 years ago
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    Its like choosing 7 teams from the 12 teams against which we win.... and from the remaining 5 teams we choose 3 teams against which we lose and from the remaining 2 teams we choose two teams against which we play tie.

  8. lgbasallote
    • 3 years ago
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    teamSSSS? isn't there only one team?

  9. sauravshakya
    • 3 years ago
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    Same thing: Replace teams with games

  10. lgbasallote
    • 3 years ago
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    yes. that does make sense

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