x-2>-5 or 5x>25

- anonymous

x-2>-5 or 5x>25

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- lgbasallote

first solve x - 2 > -5
do this by adding 2 to both sides. what do you get?

- anonymous

-3 ?

- lgbasallote

right x > -3

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## More answers

- lgbasallote

now solve 5x > 25

- anonymous

btw the said was suppose to be " greater than equal to"

- lgbasallote

which one?

- anonymous

so i just wrote greater than

- ParthKohli

Doesn't matter.

- ParthKohli

Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).

- lgbasallote

\[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\]
??

- anonymous

Yes that correct except the first one is the the greater than symbol

- lgbasallote

oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]

- anonymous

Yess

- lgbasallote

so anyway \[5x \ge 25\]
do you know how to solve for x?

- anonymous

x=5 ?

- lgbasallote

x \(\ge \) 5
the symbols matter

- lgbasallote

so since x - 2 > -5 is x > -3
and 5x \(\ge\) 25 is x\(\ge\) 5
your answer would be x > -3 or x\(\ge\) 5

- lgbasallote

@ParthKohli or is different from and

- anonymous

but when it comes to graphing x>-3 is not included

- lgbasallote

if you mean open circle..yes

- anonymous

yeah i mean open circle , greater than is always included

- lgbasallote

greater than is always included?

- anonymous

lol nvm i cant explain it here :P

- lgbasallote

i notice

- anonymous

Okay guys one more question

- lgbasallote

shoot

- anonymous

excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....

- anonymous

hahah thats exactly what i meant ^

- anonymous

sorry @lgbasallote if I interrupted you..you can carry on with your client..

- anonymous

l3xl +8>5

- lgbasallote

first of all, subtract 8 from both sides

- anonymous

yeah so its 5-8=-3

- lgbasallote

right
|3x| > -3

- anonymous

so absolute value of 3x=-3 ?

- lgbasallote

again. remember that signs matter. > is different from =

- anonymous

yeah sorry

- lgbasallote

you'll see the importance in the next step

- lgbasallote

since |3x| > -3 you turn this into two equations
3x > -3 and 3x < 3
now solve for x in each one

- anonymous

6 and 1 ?

- lgbasallote

hmm
first solve 3x > -3
divide both sides by 3

- anonymous

-1

- anonymous

x=-1 or x=1 ?

- lgbasallote

...signs...

- lgbasallote

it's not equal signs...

- anonymous

sign

- anonymous

nvm then

- lgbasallote

it should be x>-1 and x<1 signs are very important

- anonymous

Alright im done , thank you guys so much . you really helped me

- ParthKohli

@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)

- lgbasallote

in this case yes it is. but the fact remains that or is different from and

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