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x-2>-5 or 5x>25

Mathematics
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first solve x - 2 > -5 do this by adding 2 to both sides. what do you get?
-3 ?
right x > -3

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Other answers:

now solve 5x > 25
btw the said was suppose to be " greater than equal to"
which one?
so i just wrote greater than
Doesn't matter.
Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).
\[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\] ??
Yes that correct except the first one is the the greater than symbol
oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]
Yess
so anyway \[5x \ge 25\] do you know how to solve for x?
x=5 ?
x \(\ge \) 5 the symbols matter
so since x - 2 > -5 is x > -3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > -3 or x\(\ge\) 5
@ParthKohli or is different from and
but when it comes to graphing x>-3 is not included
if you mean open circle..yes
yeah i mean open circle , greater than is always included
greater than is always included?
lol nvm i cant explain it here :P
i notice
Okay guys one more question
shoot
excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....
hahah thats exactly what i meant ^
sorry @lgbasallote if I interrupted you..you can carry on with your client..
l3xl +8>5
first of all, subtract 8 from both sides
yeah so its 5-8=-3
right |3x| > -3
so absolute value of 3x=-3 ?
again. remember that signs matter. > is different from =
yeah sorry
you'll see the importance in the next step
since |3x| > -3 you turn this into two equations 3x > -3 and 3x < 3 now solve for x in each one
6 and 1 ?
hmm first solve 3x > -3 divide both sides by 3
-1
x=-1 or x=1 ?
...signs...
it's not equal signs...
sign
nvm then
it should be x>-1 and x<1 signs are very important
Alright im done , thank you guys so much . you really helped me
@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)
in this case yes it is. but the fact remains that or is different from and

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