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Shehab

  • 2 years ago

x-2>-5 or 5x>25

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  1. lgbasallote
    • 2 years ago
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    first solve x - 2 > -5 do this by adding 2 to both sides. what do you get?

  2. Shehab
    • 2 years ago
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    -3 ?

  3. lgbasallote
    • 2 years ago
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    right x > -3

  4. lgbasallote
    • 2 years ago
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    now solve 5x > 25

  5. Shehab
    • 2 years ago
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    btw the said was suppose to be " greater than equal to"

  6. lgbasallote
    • 2 years ago
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    which one?

  7. Shehab
    • 2 years ago
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    so i just wrote greater than

  8. ParthKohli
    • 2 years ago
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    Doesn't matter.

  9. ParthKohli
    • 2 years ago
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    Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).

  10. lgbasallote
    • 2 years ago
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    \[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\] ??

  11. Shehab
    • 2 years ago
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    Yes that correct except the first one is the the greater than symbol

  12. lgbasallote
    • 2 years ago
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    oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]

  13. Shehab
    • 2 years ago
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    Yess

  14. lgbasallote
    • 2 years ago
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    so anyway \[5x \ge 25\] do you know how to solve for x?

  15. Shehab
    • 2 years ago
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    x=5 ?

  16. lgbasallote
    • 2 years ago
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    x \(\ge \) 5 the symbols matter

  17. lgbasallote
    • 2 years ago
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    so since x - 2 > -5 is x > -3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > -3 or x\(\ge\) 5

  18. lgbasallote
    • 2 years ago
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    @ParthKohli or is different from and

  19. Shehab
    • 2 years ago
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    but when it comes to graphing x>-3 is not included

  20. lgbasallote
    • 2 years ago
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    if you mean open circle..yes

  21. Shehab
    • 2 years ago
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    yeah i mean open circle , greater than is always included

  22. lgbasallote
    • 2 years ago
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    greater than is always included?

  23. Shehab
    • 2 years ago
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    lol nvm i cant explain it here :P

  24. lgbasallote
    • 2 years ago
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    i notice

  25. Shehab
    • 2 years ago
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    Okay guys one more question

  26. lgbasallote
    • 2 years ago
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    shoot

  27. AbhimanyuPudi
    • 2 years ago
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    excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....

  28. Shehab
    • 2 years ago
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    hahah thats exactly what i meant ^

  29. AbhimanyuPudi
    • 2 years ago
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    sorry @lgbasallote if I interrupted you..you can carry on with your client..

  30. Shehab
    • 2 years ago
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    l3xl +8>5

  31. lgbasallote
    • 2 years ago
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    first of all, subtract 8 from both sides

  32. Shehab
    • 2 years ago
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    yeah so its 5-8=-3

  33. lgbasallote
    • 2 years ago
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    right |3x| > -3

  34. Shehab
    • 2 years ago
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    so absolute value of 3x=-3 ?

  35. lgbasallote
    • 2 years ago
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    again. remember that signs matter. > is different from =

  36. Shehab
    • 2 years ago
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    yeah sorry

  37. lgbasallote
    • 2 years ago
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    you'll see the importance in the next step

  38. lgbasallote
    • 2 years ago
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    since |3x| > -3 you turn this into two equations 3x > -3 and 3x < 3 now solve for x in each one

  39. Shehab
    • 2 years ago
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    6 and 1 ?

  40. lgbasallote
    • 2 years ago
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    hmm first solve 3x > -3 divide both sides by 3

  41. Shehab
    • 2 years ago
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    -1

  42. Shehab
    • 2 years ago
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    x=-1 or x=1 ?

  43. lgbasallote
    • 2 years ago
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    ...signs...

  44. lgbasallote
    • 2 years ago
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    it's not equal signs...

  45. Shehab
    • 2 years ago
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    sign

  46. Shehab
    • 2 years ago
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    nvm then

  47. lgbasallote
    • 2 years ago
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    it should be x>-1 and x<1 signs are very important

  48. Shehab
    • 2 years ago
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    Alright im done , thank you guys so much . you really helped me

  49. ParthKohli
    • 2 years ago
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    @lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)

  50. lgbasallote
    • 2 years ago
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    in this case yes it is. but the fact remains that or is different from and

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