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Shehab
 3 years ago
x2>5 or 5x>25
Shehab
 3 years ago
x2>5 or 5x>25

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lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0first solve x  2 > 5 do this by adding 2 to both sides. what do you get?

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1btw the said was suppose to be " greater than equal to"

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1so i just wrote greater than

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x  2=5\) and \(5x = 25\).

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0\[x  2 \ge 5 \; \text{or} \; 5x \ge 25\] ??

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1Yes that correct except the first one is the the greater than symbol

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0oh so \[x  2 > 5 ~\text{or} ~ 5x \ge 25\]

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0so anyway \[5x \ge 25\] do you know how to solve for x?

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0x \(\ge \) 5 the symbols matter

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0so since x  2 > 5 is x > 3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > 3 or x\(\ge\) 5

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0@ParthKohli or is different from and

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1but when it comes to graphing x>3 is not included

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0if you mean open circle..yes

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1yeah i mean open circle , greater than is always included

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0greater than is always included?

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1lol nvm i cant explain it here :P

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1Okay guys one more question

AbhimanyuPudi
 3 years ago
Best ResponseYou've already chosen the best response.0excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1hahah thats exactly what i meant ^

AbhimanyuPudi
 3 years ago
Best ResponseYou've already chosen the best response.0sorry @lgbasallote if I interrupted you..you can carry on with your client..

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0first of all, subtract 8 from both sides

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1so absolute value of 3x=3 ?

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0again. remember that signs matter. > is different from =

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0you'll see the importance in the next step

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0since 3x > 3 you turn this into two equations 3x > 3 and 3x < 3 now solve for x in each one

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0hmm first solve 3x > 3 divide both sides by 3

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0it's not equal signs...

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0it should be x>1 and x<1 signs are very important

Shehab
 3 years ago
Best ResponseYou've already chosen the best response.1Alright im done , thank you guys so much . you really helped me

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge 3\)

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0in this case yes it is. but the fact remains that or is different from and
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