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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
first solve x  2 > 5 do this by adding 2 to both sides. what do you get?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
right x > 3
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
now solve 5x > 25
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
btw the said was suppose to be " greater than equal to"
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
which one?
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
so i just wrote greater than
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Doesn't matter.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x  2=5\) and \(5x = 25\).
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[x  2 \ge 5 \; \text{or} \; 5x \ge 25\] ??
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
Yes that correct except the first one is the the greater than symbol
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
oh so \[x  2 > 5 ~\text{or} ~ 5x \ge 25\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so anyway \[5x \ge 25\] do you know how to solve for x?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
x \(\ge \) 5 the symbols matter
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so since x  2 > 5 is x > 3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > 3 or x\(\ge\) 5
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
@ParthKohli or is different from and
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
but when it comes to graphing x>3 is not included
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
if you mean open circle..yes
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
yeah i mean open circle , greater than is always included
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
greater than is always included?
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
lol nvm i cant explain it here :P
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i notice
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
Okay guys one more question
 2 years ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
hahah thats exactly what i meant ^
 2 years ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
sorry @lgbasallote if I interrupted you..you can carry on with your client..
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
first of all, subtract 8 from both sides
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
yeah so its 58=3
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
right 3x > 3
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
so absolute value of 3x=3 ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
again. remember that signs matter. > is different from =
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you'll see the importance in the next step
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
since 3x > 3 you turn this into two equations 3x > 3 and 3x < 3 now solve for x in each one
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm first solve 3x > 3 divide both sides by 3
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
x=1 or x=1 ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
...signs...
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it's not equal signs...
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it should be x>1 and x<1 signs are very important
 2 years ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
Alright im done , thank you guys so much . you really helped me
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge 3\)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
in this case yes it is. but the fact remains that or is different from and
 2 years ago
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