anonymous
  • anonymous
x-2>-5 or 5x>25
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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lgbasallote
  • lgbasallote
first solve x - 2 > -5 do this by adding 2 to both sides. what do you get?
anonymous
  • anonymous
-3 ?
lgbasallote
  • lgbasallote
right x > -3

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lgbasallote
  • lgbasallote
now solve 5x > 25
anonymous
  • anonymous
btw the said was suppose to be " greater than equal to"
lgbasallote
  • lgbasallote
which one?
anonymous
  • anonymous
so i just wrote greater than
ParthKohli
  • ParthKohli
Doesn't matter.
ParthKohli
  • ParthKohli
Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).
lgbasallote
  • lgbasallote
\[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\] ??
anonymous
  • anonymous
Yes that correct except the first one is the the greater than symbol
lgbasallote
  • lgbasallote
oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]
anonymous
  • anonymous
Yess
lgbasallote
  • lgbasallote
so anyway \[5x \ge 25\] do you know how to solve for x?
anonymous
  • anonymous
x=5 ?
lgbasallote
  • lgbasallote
x \(\ge \) 5 the symbols matter
lgbasallote
  • lgbasallote
so since x - 2 > -5 is x > -3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > -3 or x\(\ge\) 5
lgbasallote
  • lgbasallote
@ParthKohli or is different from and
anonymous
  • anonymous
but when it comes to graphing x>-3 is not included
lgbasallote
  • lgbasallote
if you mean open circle..yes
anonymous
  • anonymous
yeah i mean open circle , greater than is always included
lgbasallote
  • lgbasallote
greater than is always included?
anonymous
  • anonymous
lol nvm i cant explain it here :P
lgbasallote
  • lgbasallote
i notice
anonymous
  • anonymous
Okay guys one more question
lgbasallote
  • lgbasallote
shoot
anonymous
  • anonymous
excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....
anonymous
  • anonymous
hahah thats exactly what i meant ^
anonymous
  • anonymous
sorry @lgbasallote if I interrupted you..you can carry on with your client..
anonymous
  • anonymous
l3xl +8>5
lgbasallote
  • lgbasallote
first of all, subtract 8 from both sides
anonymous
  • anonymous
yeah so its 5-8=-3
lgbasallote
  • lgbasallote
right |3x| > -3
anonymous
  • anonymous
so absolute value of 3x=-3 ?
lgbasallote
  • lgbasallote
again. remember that signs matter. > is different from =
anonymous
  • anonymous
yeah sorry
lgbasallote
  • lgbasallote
you'll see the importance in the next step
lgbasallote
  • lgbasallote
since |3x| > -3 you turn this into two equations 3x > -3 and 3x < 3 now solve for x in each one
anonymous
  • anonymous
6 and 1 ?
lgbasallote
  • lgbasallote
hmm first solve 3x > -3 divide both sides by 3
anonymous
  • anonymous
-1
anonymous
  • anonymous
x=-1 or x=1 ?
lgbasallote
  • lgbasallote
...signs...
lgbasallote
  • lgbasallote
it's not equal signs...
anonymous
  • anonymous
sign
anonymous
  • anonymous
nvm then
lgbasallote
  • lgbasallote
it should be x>-1 and x<1 signs are very important
anonymous
  • anonymous
Alright im done , thank you guys so much . you really helped me
ParthKohli
  • ParthKohli
@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)
lgbasallote
  • lgbasallote
in this case yes it is. but the fact remains that or is different from and

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