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first solve x - 2 > -5
do this by adding 2 to both sides. what do you get?

-3 ?

right x > -3

now solve 5x > 25

btw the said was suppose to be " greater than equal to"

which one?

so i just wrote greater than

Doesn't matter.

\[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\]
??

Yes that correct except the first one is the the greater than symbol

oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]

Yess

so anyway \[5x \ge 25\]
do you know how to solve for x?

x=5 ?

x \(\ge \) 5
the symbols matter

@ParthKohli or is different from and

but when it comes to graphing x>-3 is not included

if you mean open circle..yes

yeah i mean open circle , greater than is always included

greater than is always included?

lol nvm i cant explain it here :P

i notice

Okay guys one more question

shoot

hahah thats exactly what i meant ^

sorry @lgbasallote if I interrupted you..you can carry on with your client..

l3xl +8>5

first of all, subtract 8 from both sides

yeah so its 5-8=-3

right
|3x| > -3

so absolute value of 3x=-3 ?

again. remember that signs matter. > is different from =

yeah sorry

you'll see the importance in the next step

since |3x| > -3 you turn this into two equations
3x > -3 and 3x < 3
now solve for x in each one

6 and 1 ?

hmm
first solve 3x > -3
divide both sides by 3

-1

x=-1 or x=1 ?

...signs...

it's not equal signs...

sign

nvm then

it should be x>-1 and x<1 signs are very important

Alright im done , thank you guys so much . you really helped me

@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)

in this case yes it is. but the fact remains that or is different from and