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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
first solve x  2 > 5 do this by adding 2 to both sides. what do you get?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
right x > 3
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
now solve 5x > 25
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
btw the said was suppose to be " greater than equal to"
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
which one?
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
so i just wrote greater than
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Doesn't matter.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x  2=5\) and \(5x = 25\).
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[x  2 \ge 5 \; \text{or} \; 5x \ge 25\] ??
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
Yes that correct except the first one is the the greater than symbol
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
oh so \[x  2 > 5 ~\text{or} ~ 5x \ge 25\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so anyway \[5x \ge 25\] do you know how to solve for x?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
x \(\ge \) 5 the symbols matter
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so since x  2 > 5 is x > 3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > 3 or x\(\ge\) 5
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
@ParthKohli or is different from and
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
but when it comes to graphing x>3 is not included
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
if you mean open circle..yes
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
yeah i mean open circle , greater than is always included
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
greater than is always included?
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
lol nvm i cant explain it here :P
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i notice
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
Okay guys one more question
 one year ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
hahah thats exactly what i meant ^
 one year ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
sorry @lgbasallote if I interrupted you..you can carry on with your client..
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
first of all, subtract 8 from both sides
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
yeah so its 58=3
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
right 3x > 3
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
so absolute value of 3x=3 ?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
again. remember that signs matter. > is different from =
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
you'll see the importance in the next step
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
since 3x > 3 you turn this into two equations 3x > 3 and 3x < 3 now solve for x in each one
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm first solve 3x > 3 divide both sides by 3
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
x=1 or x=1 ?
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
...signs...
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it's not equal signs...
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it should be x>1 and x<1 signs are very important
 one year ago

Shehab Group TitleBest ResponseYou've already chosen the best response.1
Alright im done , thank you guys so much . you really helped me
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge 3\)
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
in this case yes it is. but the fact remains that or is different from and
 one year ago
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