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Shehab

x-2>-5 or 5x>25

  • one year ago
  • one year ago

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  1. lgbasallote
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    first solve x - 2 > -5 do this by adding 2 to both sides. what do you get?

    • one year ago
  2. Shehab
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    -3 ?

    • one year ago
  3. lgbasallote
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    right x > -3

    • one year ago
  4. lgbasallote
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    now solve 5x > 25

    • one year ago
  5. Shehab
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    btw the said was suppose to be " greater than equal to"

    • one year ago
  6. lgbasallote
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    which one?

    • one year ago
  7. Shehab
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    so i just wrote greater than

    • one year ago
  8. ParthKohli
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    Doesn't matter.

    • one year ago
  9. ParthKohli
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    Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x - 2=-5\) and \(5x = 25\).

    • one year ago
  10. lgbasallote
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    \[x - 2 \ge -5 \; \text{or} \; 5x \ge 25\] ??

    • one year ago
  11. Shehab
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    Yes that correct except the first one is the the greater than symbol

    • one year ago
  12. lgbasallote
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    oh so \[x - 2 > -5 ~\text{or} ~ 5x \ge 25\]

    • one year ago
  13. Shehab
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    Yess

    • one year ago
  14. lgbasallote
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    so anyway \[5x \ge 25\] do you know how to solve for x?

    • one year ago
  15. Shehab
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    x=5 ?

    • one year ago
  16. lgbasallote
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    x \(\ge \) 5 the symbols matter

    • one year ago
  17. lgbasallote
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    so since x - 2 > -5 is x > -3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > -3 or x\(\ge\) 5

    • one year ago
  18. lgbasallote
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    @ParthKohli or is different from and

    • one year ago
  19. Shehab
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    but when it comes to graphing x>-3 is not included

    • one year ago
  20. lgbasallote
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    if you mean open circle..yes

    • one year ago
  21. Shehab
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    yeah i mean open circle , greater than is always included

    • one year ago
  22. lgbasallote
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    greater than is always included?

    • one year ago
  23. Shehab
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    lol nvm i cant explain it here :P

    • one year ago
  24. lgbasallote
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    i notice

    • one year ago
  25. Shehab
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    Okay guys one more question

    • one year ago
  26. lgbasallote
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    shoot

    • one year ago
  27. AbhimanyuPudi
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    excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....

    • one year ago
  28. Shehab
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    hahah thats exactly what i meant ^

    • one year ago
  29. AbhimanyuPudi
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    sorry @lgbasallote if I interrupted you..you can carry on with your client..

    • one year ago
  30. Shehab
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    l3xl +8>5

    • one year ago
  31. lgbasallote
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    first of all, subtract 8 from both sides

    • one year ago
  32. Shehab
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    yeah so its 5-8=-3

    • one year ago
  33. lgbasallote
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    right |3x| > -3

    • one year ago
  34. Shehab
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    so absolute value of 3x=-3 ?

    • one year ago
  35. lgbasallote
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    again. remember that signs matter. > is different from =

    • one year ago
  36. Shehab
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    yeah sorry

    • one year ago
  37. lgbasallote
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    you'll see the importance in the next step

    • one year ago
  38. lgbasallote
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    since |3x| > -3 you turn this into two equations 3x > -3 and 3x < 3 now solve for x in each one

    • one year ago
  39. Shehab
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    6 and 1 ?

    • one year ago
  40. lgbasallote
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    hmm first solve 3x > -3 divide both sides by 3

    • one year ago
  41. Shehab
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    -1

    • one year ago
  42. Shehab
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    x=-1 or x=1 ?

    • one year ago
  43. lgbasallote
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    ...signs...

    • one year ago
  44. lgbasallote
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    it's not equal signs...

    • one year ago
  45. Shehab
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    sign

    • one year ago
  46. Shehab
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    nvm then

    • one year ago
  47. lgbasallote
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    it should be x>-1 and x<1 signs are very important

    • one year ago
  48. Shehab
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    Alright im done , thank you guys so much . you really helped me

    • one year ago
  49. ParthKohli
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    @lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge -3\)

    • one year ago
  50. lgbasallote
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    in this case yes it is. but the fact remains that or is different from and

    • one year ago
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