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anonymous
 4 years ago
x2>5 or 5x>25
anonymous
 4 years ago
x2>5 or 5x>25

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first solve x  2 > 5 do this by adding 2 to both sides. what do you get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0btw the said was suppose to be " greater than equal to"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i just wrote greater than

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.1Sorry for interrupting, but you have to solve these exactly like you solve \(\rm x  2=5\) and \(5x = 25\).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x  2 \ge 5 \; \text{or} \; 5x \ge 25\] ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes that correct except the first one is the the greater than symbol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh so \[x  2 > 5 ~\text{or} ~ 5x \ge 25\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so anyway \[5x \ge 25\] do you know how to solve for x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x \(\ge \) 5 the symbols matter

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so since x  2 > 5 is x > 3 and 5x \(\ge\) 25 is x\(\ge\) 5 your answer would be x > 3 or x\(\ge\) 5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ParthKohli or is different from and

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but when it comes to graphing x>3 is not included

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you mean open circle..yes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i mean open circle , greater than is always included

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0greater than is always included?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol nvm i cant explain it here :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay guys one more question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0excluded....you have to draw a dotted line if it is greater than and you have to draw a dark complete line for greater than or equal to....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahah thats exactly what i meant ^

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry @lgbasallote if I interrupted you..you can carry on with your client..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first of all, subtract 8 from both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so absolute value of 3x=3 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0again. remember that signs matter. > is different from =

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you'll see the importance in the next step

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since 3x > 3 you turn this into two equations 3x > 3 and 3x < 3 now solve for x in each one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm first solve 3x > 3 divide both sides by 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's not equal signs...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it should be x>1 and x<1 signs are very important

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Alright im done , thank you guys so much . you really helped me

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.1@lgbasallote Try to think! If \(\rm x > 5\), it still satisfies \(\rm x\ge 3\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in this case yes it is. but the fact remains that or is different from and
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