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An engine pulls a 1500kg car on a level road at a constant speed of 5m/s against a frictional force of 500N Calculate the power expended by the engine . What extra power has the engine to expend in order to maintain the same speed of the car up an inclined plane having a gradient of 1 in 10 ?
 one year ago
 one year ago
An engine pulls a 1500kg car on a level road at a constant speed of 5m/s against a frictional force of 500N Calculate the power expended by the engine . What extra power has the engine to expend in order to maintain the same speed of the car up an inclined plane having a gradient of 1 in 10 ?
 one year ago
 one year ago

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AbhimanyuPudiBest ResponseYou've already chosen the best response.2
Power = Force x velocity Use this and you can do both on a level road and an inclined road
 one year ago

AbhimanyuPudiBest ResponseYou've already chosen the best response.2
got it? If you have any doubt, please specify.
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
1 second am doing that now
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
okay got the first part , what about the 2nd ? how to do that ?
 one year ago

AbhimanyuPudiBest ResponseYou've already chosen the best response.2
Resolve the weight mg of the car into components; one through the inclined plane and the other in the plane of the Normal Contact force....you will get N=mg x cos(theta) and the force acting opposite to the motion of thecar will be frictional force + (mg x sin(theta) ) So, now you have an extra force of mgxsin(theta) opposing the car's motion other than the frictional force...Extra power = Extra Force x velocity.......
 one year ago

AbhimanyuPudiBest ResponseYou've already chosen the best response.2
dw:1349437062303:dw
 one year ago

AbhimanyuPudiBest ResponseYou've already chosen the best response.2
got it? Is it clear now?
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
kind of , what is gradient 1 in 10 ?
 one year ago

AbhimanyuPudiBest ResponseYou've already chosen the best response.2
tan(theta) = 1/10 i guess..gradient is slope and slope=tan(theta)
 one year ago
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