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hartnnBest ResponseYou've already chosen the best response.1
know similarity of triangles ?
 one year ago

aceaceBest ResponseYou've already chosen the best response.0
yah just need help with b adn c not a
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
can u prove ABC and ACM are similar?
 one year ago

aceaceBest ResponseYou've already chosen the best response.0
yes ... its equilangular basically
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so do you know that corresponding sides of similar triangles are proportional ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
can you apply that in triangles ACM and BCM ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
oh, sorry i mentioned ABC and ACM earlier it should be ACM and BCM
 one year ago

aceaceBest ResponseYou've already chosen the best response.0
i see what you're getting at
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
if you equate corresponding sides as equal , you directly get CM^2 as AM*BM
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
for part c) you take triangles ABC and BCM
 one year ago

aceaceBest ResponseYou've already chosen the best response.0
i got AM=BM * x^2 where x was the reduction factor or ratio
 one year ago

aceaceBest ResponseYou've already chosen the best response.0
oh i did substitution... but i also got your answer
 one year ago
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