Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Arithmetic and geometric means with geometry!!!

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Question 11a and b
1 Attachment
Sorry b and c actually
know similarity of triangles ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yah just need help with b adn c not a
can u prove ABC and ACM are similar?
yes ... its equilangular basically
so do you know that corresponding sides of similar triangles are proportional ?
yes
can you apply that in triangles ACM and BCM ?
oh, sorry i mentioned ABC and ACM earlier it should be ACM and BCM
i see what you're getting at
if you equate corresponding sides as equal , you directly get CM^2 as AM*BM
sorry , proportional*
for part c) you take triangles ABC and BCM
i got AM=BM * x^2 where x was the reduction factor or ratio
what? how ?
oh i did substitution... but i also got your answer
good :)
thnx so much XD

Not the answer you are looking for?

Search for more explanations.

Ask your own question