Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

aceace

  • 2 years ago

Arithmetic and geometric means with geometry!!!

  • This Question is Closed
  1. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Question 11a and b

    1 Attachment
  2. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry b and c actually

  3. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    know similarity of triangles ?

  4. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yah just need help with b adn c not a

  5. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    can u prove ABC and ACM are similar?

  6. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes ... its equilangular basically

  7. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so do you know that corresponding sides of similar triangles are proportional ?

  8. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  9. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    can you apply that in triangles ACM and BCM ?

  10. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh, sorry i mentioned ABC and ACM earlier it should be ACM and BCM

  11. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i see what you're getting at

  12. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if you equate corresponding sides as equal , you directly get CM^2 as AM*BM

  13. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry , proportional*

  14. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    for part c) you take triangles ABC and BCM

  15. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got AM=BM * x^2 where x was the reduction factor or ratio

  16. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what? how ?

  17. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh i did substitution... but i also got your answer

  18. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    good :)

  19. aceace
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thnx so much XD

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.