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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1know similarity of triangles ?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.0yah just need help with b adn c not a

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1can u prove ABC and ACM are similar?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.0yes ... its equilangular basically

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so do you know that corresponding sides of similar triangles are proportional ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1can you apply that in triangles ACM and BCM ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1oh, sorry i mentioned ABC and ACM earlier it should be ACM and BCM

aceace
 2 years ago
Best ResponseYou've already chosen the best response.0i see what you're getting at

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if you equate corresponding sides as equal , you directly get CM^2 as AM*BM

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1for part c) you take triangles ABC and BCM

aceace
 2 years ago
Best ResponseYou've already chosen the best response.0i got AM=BM * x^2 where x was the reduction factor or ratio

aceace
 2 years ago
Best ResponseYou've already chosen the best response.0oh i did substitution... but i also got your answer
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