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 2 years ago
A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.
 2 years ago
A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.

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akash123
 2 years ago
Best ResponseYou've already chosen the best response.1find out the change in momnetum

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1then average force of resistance= rate of change of momentum= (change in momentum)/ (time interval)

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1so 1st u have to calculate..how much time bullet will take in coming to rest?

ashna
 2 years ago
Best ResponseYou've already chosen the best response.0i guess i dont understand , sorry akash am slow in this , and i want you to help me , how to calculate change in momentum ?

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1change in momentum= (final momentum initial momentum)

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1i mean... 1st the bullet was moving with a speed of 150m/s then its momentum = m(150), m=20g

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1yes use the formula v^2 u^2= 2as

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0\[V^2  u^2 = 2as\] \[\frac{ 150*150*100 }{ 2*10 } = a\]

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1if u find the acceleration, then u can calculate the average resistance force by multiplying acceleration with mass

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0Note mass shuld be in kg 1 gm = 10^3 kg

akash123
 2 years ago
Best ResponseYou've already chosen the best response.1no need to calculate change in the momentum

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0According to COD ...this is maths page...and u r asking physics...Question....Plzzz...Go..to physics page

ashna
 2 years ago
Best ResponseYou've already chosen the best response.0okay let me try , @akash123 and @Yahoo! thank yu !

ashna
 2 years ago
Best ResponseYou've already chosen the best response.0am sry i din see that .. am sry !

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0No...Problem.....and welcomee...
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