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anonymous
 4 years ago
A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.
anonymous
 4 years ago
A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find out the change in momnetum

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then average force of resistance= rate of change of momentum= (change in momentum)/ (time interval)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 1st u have to calculate..how much time bullet will take in coming to rest?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i guess i dont understand , sorry akash am slow in this , and i want you to help me , how to calculate change in momentum ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0change in momentum= (final momentum initial momentum)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i mean... 1st the bullet was moving with a speed of 150m/s then its momentum = m(150), m=20g

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes use the formula v^2 u^2= 2as

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[V^2  u^2 = 2as\] \[\frac{ 150*150*100 }{ 2*10 } = a\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if u find the acceleration, then u can calculate the average resistance force by multiplying acceleration with mass

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Note mass shuld be in kg 1 gm = 10^3 kg

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no need to calculate change in the momentum

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0According to COD ...this is maths page...and u r asking physics...Question....Plzzz...Go..to physics page

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay let me try , @akash123 and @Yahoo! thank yu !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0am sry i din see that .. am sry !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No...Problem.....and welcomee...
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