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A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.
 one year ago
 one year ago
A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.
 one year ago
 one year ago

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akash123Best ResponseYou've already chosen the best response.1
find out the change in momnetum
 one year ago

akash123Best ResponseYou've already chosen the best response.1
then average force of resistance= rate of change of momentum= (change in momentum)/ (time interval)
 one year ago

akash123Best ResponseYou've already chosen the best response.1
so 1st u have to calculate..how much time bullet will take in coming to rest?
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
i guess i dont understand , sorry akash am slow in this , and i want you to help me , how to calculate change in momentum ?
 one year ago

akash123Best ResponseYou've already chosen the best response.1
change in momentum= (final momentum initial momentum)
 one year ago

akash123Best ResponseYou've already chosen the best response.1
i mean... 1st the bullet was moving with a speed of 150m/s then its momentum = m(150), m=20g
 one year ago

akash123Best ResponseYou've already chosen the best response.1
yes use the formula v^2 u^2= 2as
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
\[V^2  u^2 = 2as\] \[\frac{ 150*150*100 }{ 2*10 } = a\]
 one year ago

akash123Best ResponseYou've already chosen the best response.1
if u find the acceleration, then u can calculate the average resistance force by multiplying acceleration with mass
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Note mass shuld be in kg 1 gm = 10^3 kg
 one year ago

akash123Best ResponseYou've already chosen the best response.1
no need to calculate change in the momentum
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
According to COD ...this is maths page...and u r asking physics...Question....Plzzz...Go..to physics page
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
okay let me try , @akash123 and @Yahoo! thank yu !
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
am sry i din see that .. am sry !
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
No...Problem.....and welcomee...
 one year ago
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