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ashna Group Title

A bullet of mass 20g moving with a speed of 150m/s atrikes a block and comes to rest after piercing 10cm into it . Find the avg. force of resistance offered by the block.

  • one year ago
  • one year ago

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  1. ashna Group Title
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    @akash123

    • one year ago
  2. akash123 Group Title
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    find out the change in momnetum

    • one year ago
  3. akash123 Group Title
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    then average force of resistance= rate of change of momentum= (change in momentum)/ (time interval)

    • one year ago
  4. akash123 Group Title
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    so 1st u have to calculate..how much time bullet will take in coming to rest?

    • one year ago
  5. akash123 Group Title
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    does it make sense?

    • one year ago
  6. ashna Group Title
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    i guess i dont understand , sorry akash am slow in this , and i want you to help me , how to calculate change in momentum ?

    • one year ago
  7. akash123 Group Title
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    change in momentum= (final momentum- initial momentum)

    • one year ago
  8. Yahoo! Group Title
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    1st find accl

    • one year ago
  9. akash123 Group Title
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    i mean... 1st the bullet was moving with a speed of 150m/s then its momentum = m(150), m=20g

    • one year ago
  10. akash123 Group Title
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    yes use the formula v^2- u^2= 2as

    • one year ago
  11. Yahoo! Group Title
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    \[V^2 - u^2 = 2as\] \[\frac{ 150*150*100 }{ 2*10 } = a\]

    • one year ago
  12. Yahoo! Group Title
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    \[F= Ma\]

    • one year ago
  13. akash123 Group Title
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    if u find the acceleration, then u can calculate the average resistance force by multiplying acceleration with mass

    • one year ago
  14. Yahoo! Group Title
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    Note mass shuld be in kg 1 gm = 10^-3 kg

    • one year ago
  15. akash123 Group Title
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    no need to calculate change in the momentum

    • one year ago
  16. Yahoo! Group Title
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    hope this helps

    • one year ago
  17. Yahoo! Group Title
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    According to COD ...this is maths page...and u r asking physics...Question....Plzzz...Go..to physics page

    • one year ago
  18. ashna Group Title
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    okay let me try , @akash123 and @Yahoo! thank yu !

    • one year ago
  19. ashna Group Title
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    am sry i din see that .. am sry !

    • one year ago
  20. Yahoo! Group Title
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    No...Problem.....and welcomee...

    • one year ago
  21. akash123 Group Title
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    :)

    • one year ago
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