A community for students.
Here's the question you clicked on:
 0 viewing
ashna
 3 years ago
Two identical 5kg blocks are moving with same speed of 2m/s towards each other along a frictionless horizontal surface . The blocks collide , stick together and comes to rest . Considering the two blocks as a system , calculate the work done by (1) external forces (2) internal forces
ashna
 3 years ago
Two identical 5kg blocks are moving with same speed of 2m/s towards each other along a frictionless horizontal surface . The blocks collide , stick together and comes to rest . Considering the two blocks as a system , calculate the work done by (1) external forces (2) internal forces

This Question is Closed

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1work done by all the forces= change in the kinetic energy

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1so what are the external forces exerting on these two blocks?

ashna
 3 years ago
Best ResponseYou've already chosen the best response.0i did'n get the question , what external and what internal ?

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1there is no friction...so only external forces are gravity and normal reaction

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1internal forces..when they'll collide with each other then they will exert forces on each other..that's the internal force

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1now will the external forces( gravity and normal reaction) do work?

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1yes...they wont do any work because they are perpendicular to d displacement...so no work done

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1so from work energy theorem work done= change in the kinetic energy > work done by external forces+ work done by the internal forces= change in the kinetic energy of the system

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1so u can calculate the work done by the internal forces

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1u know the work done by the external forces(=0) and the change in the KE of the system

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1u'll calculate the change in the KE of the system?

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1final KE=0 initial KE= 1/2 m1 v1^2 + 1/2 m2 v2^2

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1m1= m2=5kg and v1=v2=2m/s

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1so work done by internal forces= (final KE initial KE)= 20 J

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1u got the meaning of ve sign? I mean...why work done is ve?

akash123
 3 years ago
Best ResponseYou've already chosen the best response.1ve work done because they r pulling down the energy of the system to zero

ashna
 3 years ago
Best ResponseYou've already chosen the best response.0okay .. i understand ! thank you :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.