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anonymous
 4 years ago
find the critical numbers and the open intervals on which the function is increasing or decreasing.
y=3x^3+12x^2+15x
anonymous
 4 years ago
find the critical numbers and the open intervals on which the function is increasing or decreasing. y=3x^3+12x^2+15x

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2To find critical numbers for a polynomial you need to find f'(x) And set f'(x)=0 And solve for x These solutions to f'(x) will be your critical numbers

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.0lol. It took me time to realize that "critical numbers" just means "critical points". :P

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2Do you know how to find y'?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0f'(x)= 9x^2+24x+5 correct??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay now what do i do after this ? f'(x)= 9x^2+24x+15

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2Please refer to my instructions. Set f'(x)=0 and solve for x :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cant seem to be able to solve for x i got 3x(3x+8)=15

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2This is a quadratic equation You may use the quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i did that and i got 8 and 8 ; but the answers in the book are 1 and 5/3

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2So you have 9x^2+24x+15=0 correct?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2You could divide both sides by 3 since each term has a common factor 3 Giving you 3x^2+8x+5=0 Now you can do the quadratic formula but this is also pretty easy to factor

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[ax^2+bx+c=0 => x=\frac{b \pm \sqrt{b^24ac}}{2a}\] Did you use this formula?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2Then you need to try again, because 8 and 8 is not what you should get.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2What is a=? What is b=? What is c=?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a=9 b=24 c=15 correct??

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2Sure are you could have used the equation I provided you So let's plug these numbers in that you have

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[x=\frac{24 \pm \sqrt{24^24(9)(15)}}{2(9)}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2Use order of operations to evaluate what is inside the radical

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh okay i see what i did wrong i multiplied 24 by 6 instead of adding and subtracting. Thank you so much for your help!
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