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sirryan1
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Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds.
 one year ago
 one year ago
sirryan1 Group Title
Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds.
 one year ago
 one year ago

This Question is Closed

geoffb Group TitleBest ResponseYou've already chosen the best response.1
Make it into an equation. How many solutions do you expect to have?
 one year ago

sirryan1 Group TitleBest ResponseYou've already chosen the best response.0
95.1s and 108.7s 10.2s and 101.9s 108.7s and 10.2s 95.1s and 10.2s
 one year ago

geoffb Group TitleBest ResponseYou've already chosen the best response.1
Okay, it's multiple choice, so I guess the answers gave away my second question. I was asking *you*. Have you written out an equation?
 one year ago

sirryan1 Group TitleBest ResponseYou've already chosen the best response.0
@kelly226 can you help?
 one year ago

kelly226 Group TitleBest ResponseYou've already chosen the best response.0
d=1.5−53t where d is in miles and t is in hours. first divide both sides by 53 to get: d53=1.553−t this can be split into two portions: (1) for t <= 1.5/53 hours we can write: d53=1.553−t t=1.5−d53 (2) for t > 1.5/53 hours we can write: d53=−(1.553−t)=t−1.553 t=1.5+d53
 one year ago

sirryan1 Group TitleBest ResponseYou've already chosen the best response.0
i dont get it
 one year ago

geoffb Group TitleBest ResponseYou've already chosen the best response.1
Of course you don't. You haven't written out an equation yourself. It makes perfect sense that you don't understand it.
 one year ago
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