kymber
  • kymber
How to find the maximum or minimum value of a quadratic function?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
You look at the vertex. Are you at the calculus level or the algebra level?
ganeshie8
  • ganeshie8
see the sign of x^2 coeffecient
kymber
  • kymber
Algrebra II, year three in high school. It's the same as the vertex?

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ganeshie8
  • ganeshie8
correct, vertex gives us max/min value. if x^2 coefficient is -ve, its min if x^2 coefficient is +ve, its max
ganeshie8
  • ganeshie8
its the opposite actually. if x^2 coefficient is -ve, its max if x^2 coefficient is +ve, its min
anonymous
  • anonymous
What @ganeshie8 said, that will tell you whether the parabola faces up or down. The point at the vertex will be a min or a max depending on that coefficient.
ganeshie8
  • ganeshie8
|dw:1349465625929:dw|
ganeshie8
  • ganeshie8
so we have minimum value there
kymber
  • kymber
So how do you find the value of it?
ganeshie8
  • ganeshie8
max/min value = f(-b/2a)
ganeshie8
  • ganeshie8
actually it comes from the formula for vertex, vertex = (-b/2a, f(-b/2a))
phi
  • phi
for parabola f(x)= a x^2 + b x +c the x coordinate of the vertex is -b/(2a)
kymber
  • kymber
Um, like this? |dw:1349465829395:dw|
anonymous
  • anonymous
Given \[ax^2+bx+c=a(x-h)^2+k\] The vertex is located at (h, k).
ganeshie8
  • ganeshie8
|dw:1349465949629:dw|
ganeshie8
  • ganeshie8
that gives the x-coordinate only, y-coordinate gives the max/min value.
ganeshie8
  • ganeshie8
coordinate is just a number i think
kymber
  • kymber
So how do I find the y-coordinate?
ganeshie8
  • ganeshie8
since you got, x-coordinate of vertex = -b/2a = 5
ganeshie8
  • ganeshie8
put that x value = 5, in the quadratic, it gives u y-coordinate of vertex
phi
  • phi
notice in x^2 -10x +25 b is -10 (negative 10) -b/2a is +10/2*1= 10/2 = +5 use 5 for x in the equation to find the y value
kymber
  • kymber
I got it! Thanks guys \(\Large\ddot\smile\)
ganeshie8
  • ganeshie8
glad to hear friend :)
phi
  • phi
hopefully you got y=0 so the vertex is at (5,0) and the min value is 0
ganeshie8
  • ganeshie8
and hw do i get that
ganeshie8
  • ganeshie8
smiley..
kymber
  • kymber
Yep, I got 0. the smiley is \large\ddot\smile :P
ganeshie8
  • ganeshie8
\( \large\ddot\smile \) ah latex is beautifyul :)
kymber
  • kymber
Yes it is :D
anonymous
  • anonymous
Thanks, @kymber for teaching us something. \[\large \ddot \smile\] Awesome.
kymber
  • kymber
Hehe \(\huge\ddot\smile\)
hartnn
  • hartnn
yeah , kymber also taught me to draw heart ♥ \(\huge \color{red}{♥}\)
anonymous
  • anonymous
Nice!
kymber
  • kymber
\(\Huge\color{pink}{❥}\) Sideways!
ganeshie8
  • ganeshie8
i thought only AccessDenied is the latex guru... we have so many experts over here hmm :)
ganeshie8
  • ganeshie8
but thats cheating... thats not latex, u using unicode i guess
anonymous
  • anonymous
You're blowing my mind, @kymber !
kymber
  • kymber
Lol yeah.. it's not a \(\LaTeX\) command. Just alt codes :|
hartnn
  • hartnn
still its cool :)
kymber
  • kymber
:D
ganeshie8
  • ganeshie8
:) yea these things i can see also. but sometime back i tried to use crossed swords unicode, and it didnt show up in many browsers :( from then i stopped using unicode, not sure why only few unicode characters show up...
ganeshie8
  • ganeshie8
this one : http://www.fileformat.info/info/unicode/char/2694/index.htm see if u can get this here...
kymber
  • kymber
\(\Huge{⚔}\)
kymber
  • kymber
Lol.
ganeshie8
  • ganeshie8
i see a box, what u see at ur end hmm
kymber
  • kymber
:| I see the swords..
hartnn
  • hartnn
i see box also
kymber
  • kymber
What browser are you guys using?
hartnn
  • hartnn
chrome O.o
ganeshie8
  • ganeshie8
chrome too
kymber
  • kymber
I'm using Mozilla :P
ganeshie8
  • ganeshie8
firefox ?
hartnn
  • hartnn
letme login through mozilla
kymber
  • kymber
Yeah. I switched to Chrome and it's a box. Use Mozilla! :P
ganeshie8
  • ganeshie8
mozilla wins !
hartnn
  • hartnn
what kind of black magic is this!
anonymous
  • anonymous
Firefox is simply superior . .

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