Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Help please? :o 1. Solve the system by substitution- 2x+y=-11, 3x-4y=11. I'm so terrible at substitution and elimination >.< 2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10. 3.What is the solution of the following system?-3x-2y=-12, 9x+6y=-9. Help with any of these would be greatly appreciated thanks.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Even any tips on how to do these would be nice :/
ok so looking at the first one. basically you have to multiply one or both of the equations by a number so that the coefficient of one of the variables is the same so that when you subtract/add them then it will cancel. ^that sounds confusing, here's an ex for elimination: x+y=5, 2x+y = 30 so if we multiplied the first equation by 2, we'd get: 2x+2y=10 right? so we can subtract now... 2x+2y=10 - 2x+y=30 ------------ 0 + y = -20 ------------- and now we can plug in -20 for y back in the equation to find x. hope that made sense
Yeah that made more sense than my textbook does haha. How about a substitution example? Or how you can tell if a system is dependant or independant? or has infinately many solutions?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

haha yeah textbooks can be annoying sometimes. so substitution: x+y=2 x+4y = 7 so in substitution we basically just have to get any variable on its own so that we can substitute it into another equation. pretty much cause solving for 2 variables is hard. so i can get either x or y by itself from the 1st equation (or the second if you want). x+y = 2 so x+y-y = 2-y so, x+0=2-y or x=2-y now we know what x equals, so lets put it in the other equation. (x) +4y=7 OR (2-y) +4y = 7 [see what i did there? ] so 2-y+4y=7, 2+3y=7, 3y=5, y=5/3 and you can put this in the x equation (x=2-y) to get x aswell :)
Very much so >.< Man that all still seems pretty confusing but I really appreciate the help! I always just tend to get one step wrong along the way and mess the whole thing up lol, It's in my nature :P
x-y=11, -x+y=-11 Would one like this have infinitely many solutions?
same here. i used to hate math so much, i still sort of suck at it. even if i get the stuff i make little mistakes. <.< anyway, if you just practice it a bit i'm sure you'll get it. yeah that would have infinitely many solutions because they're the same equation just written differently. so on a graph, there would be just the one line. this might help: http://www.mathocean.com/2009/10/system-of-linear-equations-consistency.html
Well I'll keep trying x.x I just need to do decently on my daily tests which so far I haven't really haha. And yeah that's what i though lol. Funny I swear I've been to that website before x)
daily tests? ai yi yi. haha well that's good, good luck!
Yeah every day, about 10 question tests x.x it's ridiculous.. But thanks !
woah that is a little ridiculous. well you get practice from it i suppose. yeah no problem :D

Not the answer you are looking for?

Search for more explanations.

Ask your own question