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anonymous
 4 years ago
wo charges, Q1 = 4.00 μC and Q2 = 6.80 μC, are located at points (0, 2.65 cm) and (0, +2.65 cm), as shown in the figure.
What is the magnitude of the electric field at point P, located at (6.15 cm, 0), due to Q1 alone?
anonymous
 4 years ago
wo charges, Q1 = 4.00 μC and Q2 = 6.80 μC, are located at points (0, 2.65 cm) and (0, +2.65 cm), as shown in the figure. What is the magnitude of the electric field at point P, located at (6.15 cm, 0), due to Q1 alone?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349471622020:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@demitris could u help me with this one last question,and thanks for the others u did.got it right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is the xcomponent of the total electric field at P? What is the ycomponent of the total electric field at P? What is the magnitude of the total electric field at P?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Did you get your answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349477252753:dw E1 is electric field due to q1. \[E_1=\frac{1}{4\pi\epsilon_0 }\frac{q_1}{r^2} \] making angle \[\theta=\arctan{\frac{y}{x}}\]with horizontal.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, now here's the strategy: 1) Find the magnitude of E1 first (you already did it in no 1) 2) Find the magnitude of E2 (no useto do this, since both q1 and q2 has the same charge) 3) Find x component of E1 and E2 (actually you just need to find x component of E1. E2 has the same x component). 4) Find y component of E1 and E2 (the total y component of E1 and E2 cancels each other. Since they have same magnitude but opposite direction)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@imron07 not quite right. q1 and q2 are different.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Haha, thanks @Algebraic! . I thought they have common charge.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349681562544:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0r^2=(X2X1)^2(Y2Y1)^2 distance formula
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