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krypton

wo charges, Q1 = 4.00 μC and Q2 = 6.80 μC, are located at points (0, -2.65 cm) and (0, +2.65 cm), as shown in the figure. What is the magnitude of the electric field at point P, located at (6.15 cm, 0), due to Q1 alone?

  • one year ago
  • one year ago

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  1. krypton
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    |dw:1349471622020:dw|

    • one year ago
  2. krypton
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    @demitris could u help me with this one last question,and thanks for the others u did.got it right

    • one year ago
  3. krypton
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    What is the x-component of the total electric field at P? What is the y-component of the total electric field at P? What is the magnitude of the total electric field at P?

    • one year ago
  4. imron07
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    Did you get your answer?

    • one year ago
  5. krypton
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    NOT YET :(

    • one year ago
  6. krypton
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    GOT ONLY NUMBER 1

    • one year ago
  7. imron07
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    |dw:1349477252753:dw| E1 is electric field due to q1. \[E_1=\frac{1}{4\pi\epsilon_0 }\frac{q_1}{r^2} \] making angle \[\theta=\arctan{\frac{y}{x}}\]with horizontal.

    • one year ago
  8. imron07
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    Okay, now here's the strategy: 1) Find the magnitude of E1 first (you already did it in no 1) 2) Find the magnitude of E2 (no useto do this, since both q1 and q2 has the same charge) 3) Find x component of E1 and E2 (actually you just need to find x component of E1. E2 has the same x component). 4) Find y component of E1 and E2 (the total y component of E1 and E2 cancels each other. Since they have same magnitude but opposite direction)

    • one year ago
  9. Algebraic!
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    @imron07 not quite right. q1 and q2 are different.

    • one year ago
  10. imron07
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    Haha, thanks @Algebraic! . I thought they have common charge.

    • one year ago
  11. 03225186213
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    |dw:1349681562544:dw|

    • one year ago
  12. 03225186213
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    r^2=(X2-X1)^2-(Y2-Y1)^2 distance formula

    • one year ago
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