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wo charges, Q1 = 4.00 μC and Q2 = 6.80 μC, are located at points (0, 2.65 cm) and (0, +2.65 cm), as shown in the figure.
What is the magnitude of the electric field at point P, located at (6.15 cm, 0), due to Q1 alone?
 one year ago
 one year ago
wo charges, Q1 = 4.00 μC and Q2 = 6.80 μC, are located at points (0, 2.65 cm) and (0, +2.65 cm), as shown in the figure. What is the magnitude of the electric field at point P, located at (6.15 cm, 0), due to Q1 alone?
 one year ago
 one year ago

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kryptonBest ResponseYou've already chosen the best response.0
@demitris could u help me with this one last question,and thanks for the others u did.got it right
 one year ago

kryptonBest ResponseYou've already chosen the best response.0
What is the xcomponent of the total electric field at P? What is the ycomponent of the total electric field at P? What is the magnitude of the total electric field at P?
 one year ago

imron07Best ResponseYou've already chosen the best response.1
Did you get your answer?
 one year ago

imron07Best ResponseYou've already chosen the best response.1
dw:1349477252753:dw E1 is electric field due to q1. \[E_1=\frac{1}{4\pi\epsilon_0 }\frac{q_1}{r^2} \] making angle \[\theta=\arctan{\frac{y}{x}}\]with horizontal.
 one year ago

imron07Best ResponseYou've already chosen the best response.1
Okay, now here's the strategy: 1) Find the magnitude of E1 first (you already did it in no 1) 2) Find the magnitude of E2 (no useto do this, since both q1 and q2 has the same charge) 3) Find x component of E1 and E2 (actually you just need to find x component of E1. E2 has the same x component). 4) Find y component of E1 and E2 (the total y component of E1 and E2 cancels each other. Since they have same magnitude but opposite direction)
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
@imron07 not quite right. q1 and q2 are different.
 one year ago

imron07Best ResponseYou've already chosen the best response.1
Haha, thanks @Algebraic! . I thought they have common charge.
 one year ago

03225186213Best ResponseYou've already chosen the best response.0
dw:1349681562544:dw
 one year ago

03225186213Best ResponseYou've already chosen the best response.0
r^2=(X2X1)^2(Y2Y1)^2 distance formula
 one year ago
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