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elizabethann509
Group Title
How do you solve something like this?
2x  3 ≥ 21
 2 years ago
 2 years ago
elizabethann509 Group Title
How do you solve something like this? 2x  3 ≥ 21
 2 years ago
 2 years ago

This Question is Closed

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Same way you solve a normal equation, but if you multiply or divide by a negative number, you have to switch the direction of the inequality symbol.
 2 years ago

Geometry_Hater Group TitleBest ResponseYou've already chosen the best response.0
Just do it as normal Get x by itself
 2 years ago

BreannaKawaii Group TitleBest ResponseYou've already chosen the best response.2
add 3 to both sides = 2x ≥ 24 , now divide by 2 to isolate x , giving you x LESS THAN OR EQUAL TO (sign flips when dividing by negatives) 12
 2 years ago

elizabethann509 Group TitleBest ResponseYou've already chosen the best response.0
Thanks everyone! Makes sense now. That was easy :)
 2 years ago

sue101 Group TitleBest ResponseYou've already chosen the best response.0
2x  3 2x  3 ≥ 21 21 Add 3 to both sides +3 +3  2x ≥ 24 Divide by  2 /2 /2  x ≥ 12
 2 years ago
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