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anonymous
 3 years ago
How do you solve something like this?
2x  3 ≥ 21
anonymous
 3 years ago
How do you solve something like this? 2x  3 ≥ 21

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Same way you solve a normal equation, but if you multiply or divide by a negative number, you have to switch the direction of the inequality symbol.

Geometry_Hater
 3 years ago
Best ResponseYou've already chosen the best response.0Just do it as normal Get x by itself

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0add 3 to both sides = 2x ≥ 24 , now divide by 2 to isolate x , giving you x LESS THAN OR EQUAL TO (sign flips when dividing by negatives) 12

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks everyone! Makes sense now. That was easy :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02x  3 2x  3 ≥ 21 21 Add 3 to both sides +3 +3  2x ≥ 24 Divide by  2 /2 /2  x ≥ 12
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