Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
elizabethann509
Group Title
How do you solve something like this?
2x  3 ≥ 21
 one year ago
 one year ago
elizabethann509 Group Title
How do you solve something like this? 2x  3 ≥ 21
 one year ago
 one year ago

This Question is Closed

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Same way you solve a normal equation, but if you multiply or divide by a negative number, you have to switch the direction of the inequality symbol.
 one year ago

Geometry_Hater Group TitleBest ResponseYou've already chosen the best response.0
Just do it as normal Get x by itself
 one year ago

BreannaKawaii Group TitleBest ResponseYou've already chosen the best response.2
add 3 to both sides = 2x ≥ 24 , now divide by 2 to isolate x , giving you x LESS THAN OR EQUAL TO (sign flips when dividing by negatives) 12
 one year ago

elizabethann509 Group TitleBest ResponseYou've already chosen the best response.0
Thanks everyone! Makes sense now. That was easy :)
 one year ago

sue101 Group TitleBest ResponseYou've already chosen the best response.0
2x  3 2x  3 ≥ 21 21 Add 3 to both sides +3 +3  2x ≥ 24 Divide by  2 /2 /2  x ≥ 12
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.