A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
How do you solve something like this?
2x  3 ≥ 21
anonymous
 4 years ago
How do you solve something like this? 2x  3 ≥ 21

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Same way you solve a normal equation, but if you multiply or divide by a negative number, you have to switch the direction of the inequality symbol.

Geometry_Hater
 4 years ago
Best ResponseYou've already chosen the best response.0Just do it as normal Get x by itself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0add 3 to both sides = 2x ≥ 24 , now divide by 2 to isolate x , giving you x LESS THAN OR EQUAL TO (sign flips when dividing by negatives) 12

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks everyone! Makes sense now. That was easy :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02x  3 2x  3 ≥ 21 21 Add 3 to both sides +3 +3  2x ≥ 24 Divide by  2 /2 /2  x ≥ 12
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.