## remnant Group Title Please help with the following factorial example: one year ago one year ago

Okay i'll just give the answer:$\frac{(2n+2)!n!}{2n!(n+1)!}=\frac{(2n+2)(2n+1)!n!}{2n!(n+1)n!}=\frac{(2n+2)(2n+1)(2n)!n!}{2n!(n+1)n!}$