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Show the conjecture is false by finding a counterexample.
The product of (a+b)^2 is equal to a^2 +b^2, for a is not equal to 0, and b is not equal to 0.
 one year ago
 one year ago
Show the conjecture is false by finding a counterexample. The product of (a+b)^2 is equal to a^2 +b^2, for a is not equal to 0, and b is not equal to 0.
 one year ago
 one year ago

This Question is Closed

imron07Best ResponseYou've already chosen the best response.3
Say, a=3 and b=4 (3+4)^2=49 3^2+4^2=9+16=25 Which is not equal to 49.
 one year ago
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