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gifty91
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Superman dangles his watch from a thin piece of string while he is taking off from the ground horizontally at a constant acceleration a. He notices that the string makes an angle (theta) with respect to the vertical. After 20 seconds, his speed is v=134 m/s. Estimate the angle (theta).
 one year ago
 one year ago
gifty91 Group Title
Superman dangles his watch from a thin piece of string while he is taking off from the ground horizontally at a constant acceleration a. He notices that the string makes an angle (theta) with respect to the vertical. After 20 seconds, his speed is v=134 m/s. Estimate the angle (theta).
 one year ago
 one year ago

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CreAtivSpelErr Group TitleBest ResponseYou've already chosen the best response.1
Use the time and final velocity to find the horizontal acceleration. Use Newton's 2nd Law and do a vector triangle with forces. The vertical force is mg, the horizontal force is ma (the force superman needs to exert on the watch to give it a horizontal acceleration of 'a'). \[\tan \theta = \frac{ mg }{ ma }\] and the unknown mass of the watch cancels.
 one year ago

gifty91 Group TitleBest ResponseYou've already chosen the best response.0
I got 6.7 m/s^2 for the horizontal acceleration, and for theta I got 55.6 degrees but apparently that's wrong. I calculated the acceleration as final velocityinitial velocity/time, so the acceleration, I'm assuming should be correct. Not sure what I did wrong after that.
 one year ago

masumanwar Group TitleBest ResponseYou've already chosen the best response.0
they can understand every problem they need to go through treatment to
 one year ago
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