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MrOrbit

  • 2 years ago

How do I solve this? \[-7\sqrt[2]{3x-8} + 3 = -4x + 7\]

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  1. MrOrbit
    • 2 years ago
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    \[-7\sqrt[2]{3x-8} + 3 = -4x + 7\]

  2. imron07
    • 2 years ago
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    \[-7\sqrt{3x-8}=-4x+4\\ \sqrt{3x-8}=\frac{-4x+7}{-7}\] then square both sides.

  3. MrOrbit
    • 2 years ago
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    But there is a 2 infront of the square root of 2x-8 How do i get rid of that?

  4. Compassionate
    • 2 years ago
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    You want to start first by solving the squareroot.

  5. imron07
    • 2 years ago
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    Don't you think that 2 simply means square root.

  6. ChmE
    • 2 years ago
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    @imron07 is right. if there were a 3 there it would mean ^(1/3). The 2 just means ^(1/2) which is the same thing as square root

  7. MrOrbit
    • 2 years ago
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    Oh that makes so much sense. Thanks guys, I really appreciate it.

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