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## MrOrbit 3 years ago How do I solve this? $-7\sqrt[2]{3x-8} + 3 = -4x + 7$

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1. MrOrbit

$-7\sqrt[2]{3x-8} + 3 = -4x + 7$

2. imron07

$-7\sqrt{3x-8}=-4x+4\\ \sqrt{3x-8}=\frac{-4x+7}{-7}$ then square both sides.

3. MrOrbit

But there is a 2 infront of the square root of 2x-8 How do i get rid of that?

4. Compassionate

You want to start first by solving the squareroot.

5. imron07

Don't you think that 2 simply means square root.

6. ChmE

@imron07 is right. if there were a 3 there it would mean ^(1/3). The 2 just means ^(1/2) which is the same thing as square root

7. MrOrbit

Oh that makes so much sense. Thanks guys, I really appreciate it.

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