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MrOrbit Group Title

How do I solve this? \[-7\sqrt[2]{3x-8} + 3 = -4x + 7\]

  • 2 years ago
  • 2 years ago

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  1. MrOrbit Group Title
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    \[-7\sqrt[2]{3x-8} + 3 = -4x + 7\]

    • 2 years ago
  2. imron07 Group Title
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    \[-7\sqrt{3x-8}=-4x+4\\ \sqrt{3x-8}=\frac{-4x+7}{-7}\] then square both sides.

    • 2 years ago
  3. MrOrbit Group Title
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    But there is a 2 infront of the square root of 2x-8 How do i get rid of that?

    • 2 years ago
  4. Compassionate Group Title
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    You want to start first by solving the squareroot.

    • 2 years ago
  5. imron07 Group Title
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    Don't you think that 2 simply means square root.

    • 2 years ago
  6. ChmE Group Title
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    @imron07 is right. if there were a 3 there it would mean ^(1/3). The 2 just means ^(1/2) which is the same thing as square root

    • 2 years ago
  7. MrOrbit Group Title
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    Oh that makes so much sense. Thanks guys, I really appreciate it.

    • 2 years ago
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