## anonymous 3 years ago How do I solve this? $-7\sqrt[2]{3x-8} + 3 = -4x + 7$

1. anonymous

$-7\sqrt[2]{3x-8} + 3 = -4x + 7$

2. anonymous

$-7\sqrt{3x-8}=-4x+4\\ \sqrt{3x-8}=\frac{-4x+7}{-7}$ then square both sides.

3. anonymous

But there is a 2 infront of the square root of 2x-8 How do i get rid of that?

4. Compassionate

You want to start first by solving the squareroot.

5. anonymous

Don't you think that 2 simply means square root.

6. anonymous

@imron07 is right. if there were a 3 there it would mean ^(1/3). The 2 just means ^(1/2) which is the same thing as square root

7. anonymous

Oh that makes so much sense. Thanks guys, I really appreciate it.