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kcla1996 Group Title

Use the diagram to find sin X as a fraction in simplest form.

  • one year ago
  • one year ago

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  1. kcla1996 Group Title
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    • one year ago
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  2. geoffb Group Title
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    Okay, what is the sin function? What two sides?

    • one year ago
  3. kcla1996 Group Title
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    um im not too sure

    • one year ago
  4. geoffb Group Title
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    SOHCAHTOA. Remember that for the rest of your life. ;)

    • one year ago
  5. geoffb Group Title
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    Sin = Opposite / Hypotenuse Cos = Adjacent / Hypotenuse Tan = Opposite / Adjacent You will use those a lot.

    • one year ago
  6. kcla1996 Group Title
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    what? haha

    • one year ago
  7. kcla1996 Group Title
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    i still don't get it....

    • one year ago
  8. geoffb Group Title
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    Do you know what opposite and adjacent mean, relative to the angle, X, in the triangle?

    • one year ago
  9. kcla1996 Group Title
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    idk if this is right: adjacent is 36 opposite is 60 and hypotenuse is 48 ?

    • one year ago
  10. geoffb Group Title
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    You're right about adjacent. The other two, you have mixed up. Opposite will always be the only side of the triangle that doesn't touch the angle you're looking at. The hypotenuse (in a right angle triangle) is always the side across from (not touching) the right angle. Also, the hypotenuse will *always* be the longest side.

    • one year ago
  11. kcla1996 Group Title
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    sin: 48/60 cos: 36/60 tan: 48/36 is this correct?

    • one year ago
  12. geoffb Group Title
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    Yes! You've got the premise. The only issue is with how you've written it. Technically, the value of your angle (in degrees) is equal to sin(48/60), cos(36/60), or tan(48/36).

    • one year ago
  13. geoffb Group Title
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    You know X = sin(48/60), all that's left is the question asks for a fraction in simplest form.

    • one year ago
  14. kcla1996 Group Title
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    4/5

    • one year ago
  15. geoffb Group Title
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    Sorry, I was thinking backward. It's not X = sin(4/5). It's sin X = 4/5. So yes, that is perfect.

    • one year ago
  16. kcla1996 Group Title
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    thankies!! ;D

    • one year ago
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