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kcla1996 Group Title

Use the diagram to find sin X as a fraction in simplest form.

  • 2 years ago
  • 2 years ago

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  1. kcla1996 Group Title
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    • 2 years ago
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  2. geoffb Group Title
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    Okay, what is the sin function? What two sides?

    • 2 years ago
  3. kcla1996 Group Title
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    um im not too sure

    • 2 years ago
  4. geoffb Group Title
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    SOHCAHTOA. Remember that for the rest of your life. ;)

    • 2 years ago
  5. geoffb Group Title
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    Sin = Opposite / Hypotenuse Cos = Adjacent / Hypotenuse Tan = Opposite / Adjacent You will use those a lot.

    • 2 years ago
  6. kcla1996 Group Title
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    what? haha

    • 2 years ago
  7. kcla1996 Group Title
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    i still don't get it....

    • 2 years ago
  8. geoffb Group Title
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    Do you know what opposite and adjacent mean, relative to the angle, X, in the triangle?

    • 2 years ago
  9. kcla1996 Group Title
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    idk if this is right: adjacent is 36 opposite is 60 and hypotenuse is 48 ?

    • 2 years ago
  10. geoffb Group Title
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    You're right about adjacent. The other two, you have mixed up. Opposite will always be the only side of the triangle that doesn't touch the angle you're looking at. The hypotenuse (in a right angle triangle) is always the side across from (not touching) the right angle. Also, the hypotenuse will *always* be the longest side.

    • 2 years ago
  11. kcla1996 Group Title
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    sin: 48/60 cos: 36/60 tan: 48/36 is this correct?

    • 2 years ago
  12. geoffb Group Title
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    Yes! You've got the premise. The only issue is with how you've written it. Technically, the value of your angle (in degrees) is equal to sin(48/60), cos(36/60), or tan(48/36).

    • 2 years ago
  13. geoffb Group Title
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    You know X = sin(48/60), all that's left is the question asks for a fraction in simplest form.

    • 2 years ago
  14. kcla1996 Group Title
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    4/5

    • 2 years ago
  15. geoffb Group Title
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    Sorry, I was thinking backward. It's not X = sin(4/5). It's sin X = 4/5. So yes, that is perfect.

    • 2 years ago
  16. kcla1996 Group Title
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    thankies!! ;D

    • 2 years ago
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