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kcla1996 Group Title

Find the distance between the two points. Round to the nearest tenth if necessary. (2, 5) and (–1, –5)

  • one year ago
  • one year ago

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  1. ash.vasvani Group Title
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    Make a triangle, Pythagorean theorem.

    • one year ago
  2. hartnn Group Title
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    or you could use this : Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)

    • one year ago
  3. CliffSedge Group Title
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    Distance formula is derived from Pythagoras' Theorem, I've found it's easier for students to remember the one formula than have to memorize another one.

    • one year ago
  4. CliffSedge Group Title
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    |dw:1349496154838:dw|

    • one year ago
  5. CliffSedge Group Title
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    It's easy enough to see what the lengths of the legs of the triangle are, then solve for the hypotenuse.

    • one year ago
  6. kcla1996 Group Title
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    1?

    • one year ago
  7. kcla1996 Group Title
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    Here are the choices: A. 1 B. 109 C. 10.4 D. 3

    • one year ago
  8. kcla1996 Group Title
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    is 1 the correct answer?

    • one year ago
  9. CliffSedge Group Title
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    |dw:1349496503466:dw|

    • one year ago
  10. CliffSedge Group Title
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    1 doesn't seem very reasonable for points that far apart.

    • one year ago
  11. kcla1996 Group Title
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    10.4?

    • one year ago
  12. CliffSedge Group Title
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    That seems more reasonable, but how can you be sure? What if it wasn't a multiple choice question and you had to provide an exact value, not just one rounded to the tenths' place?

    • one year ago
  13. kcla1996 Group Title
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    oh i just counted how long the triangle's height was on the picture you drew, and i counted 10

    • one year ago
  14. kcla1996 Group Title
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    is it right?

    • one year ago
  15. CliffSedge Group Title
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    Ah, no. You have to use Pythagorean Theorem to find the hypotenuse of the right triangle. |dw:1349498042456:dw| Or perhaps you would have been better off using the distance formula hart provided..

    • one year ago
  16. kcla1996 Group Title
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    ok i'll try it....i'll tell you what i get

    • one year ago
  17. kcla1996 Group Title
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    oh wait

    • one year ago
  18. kcla1996 Group Title
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    how do i put (2,5) and (-1,-5) in that equation

    • one year ago
  19. AriPotta Group Title
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    coordinates are (x,y) so substitute the coordinates' x's and y's

    • one year ago
  20. kcla1996 Group Title
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    109?

    • one year ago
  21. hartnn Group Title
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    yup, now don't forget to take aquare root.

    • one year ago
  22. hartnn Group Title
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    *square

    • one year ago
  23. kcla1996 Group Title
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    oh thank you! so it's 10.4 :D

    • one year ago
  24. hartnn Group Title
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    welcome :)

    • one year ago
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