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integrate 1/(5+sinx-3cosx) let u = tan(x/2) cosx = (1-u^2)/(1+u^2) sinx = 2u/(1+u^2) dx = 2/(1+u^2)

Mathematics
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Oh my god... This is a monster to integrate...
yeah, after substituting everything i got up to 1/[4(u+(1/8))^2 + (15/64)]
if you could help me with that, that'd be cool. I don't know what to do next to integrate

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Other answers:

You don't have to use intergration by parts. You can use substitution twice.
?
Nevermind. I am wrong.
Dammit. Sorry. I can't solve this :( . It's beyond my level of math.
quick unrelated question: if i have 1/u(1-u^2) can i use partial fractions to integrate? even though its (-u^2 + 1) in the denom? i never came across a negative like that
I don't think so... Sorry. I can't help you any further with this :( .
that's okay, thanks for looking though
i know igbasallote got dis
level 99 math wizard
I would love to see how to do this question.
I GOT IT, BUT VERY LONG TO WRITTING THIS STEPS :(
as information (if im not mistake), i got the answer : |dw:1349498667471:dw|
yes, i think my answer is right ^^,, bacasue the "god of math" told me that : http://www.wolframalpha.com/input/?i=int%28dx%2F%285%2Bsin%28x%29-3cos%28x%29%29%29

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