anonymous
  • anonymous
integrate 1/(5+sinx-3cosx) let u = tan(x/2) cosx = (1-u^2)/(1+u^2) sinx = 2u/(1+u^2) dx = 2/(1+u^2)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Oh my god... This is a monster to integrate...
anonymous
  • anonymous
yeah, after substituting everything i got up to 1/[4(u+(1/8))^2 + (15/64)]
anonymous
  • anonymous
if you could help me with that, that'd be cool. I don't know what to do next to integrate

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anonymous
  • anonymous
You don't have to use intergration by parts. You can use substitution twice.
anonymous
  • anonymous
?
anonymous
  • anonymous
Nevermind. I am wrong.
anonymous
  • anonymous
Dammit. Sorry. I can't solve this :( . It's beyond my level of math.
anonymous
  • anonymous
quick unrelated question: if i have 1/u(1-u^2) can i use partial fractions to integrate? even though its (-u^2 + 1) in the denom? i never came across a negative like that
anonymous
  • anonymous
I don't think so... Sorry. I can't help you any further with this :( .
anonymous
  • anonymous
that's okay, thanks for looking though
anonymous
  • anonymous
i know igbasallote got dis
anonymous
  • anonymous
level 99 math wizard
anonymous
  • anonymous
I would love to see how to do this question.
RadEn
  • RadEn
I GOT IT, BUT VERY LONG TO WRITTING THIS STEPS :(
RadEn
  • RadEn
as information (if im not mistake), i got the answer : |dw:1349498667471:dw|
RadEn
  • RadEn
yes, i think my answer is right ^^,, bacasue the "god of math" told me that : http://www.wolframalpha.com/input/?i=int%28dx%2F%285%2Bsin%28x%29-3cos%28x%29%29%29

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