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Express the inverse of the following matrix (assuming it exists) as a matrix containing expressions in terms of k.
3 0 k
12 8 16
4 2 4
 one year ago
 one year ago
Express the inverse of the following matrix (assuming it exists) as a matrix containing expressions in terms of k. 3 0 k 12 8 16 4 2 4
 one year ago
 one year ago

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zzr0ck3rBest ResponseYou've already chosen the best response.0
um you gave a list of numbers that in no way resembles a matrix
 one year ago

iop360Best ResponseYou've already chosen the best response.0
\[\left[\begin{matrix}3 & 0 & k \\ 12 & 8 & 16\\ 4 & 2 & 4\end{matrix}\right]^{1}\]
 one year ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
can you reduce it to I?
 one year ago

iop360Best ResponseYou've already chosen the best response.0
i write where i am write now
 one year ago

zzr0ck3rBest ResponseYou've already chosen the best response.0
k brb wife just got home.
 one year ago

iop360Best ResponseYou've already chosen the best response.0
this is just the coefficient matrix\[\left[\begin{matrix}1 & 0 & 0 \\ 0 & 1 & 2\\ 0 & 0 & k\end{matrix}\right]\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
Use GaussJordan elimination on \[\left[\begin{matrix}3 & 0 & k & 1 & 0 & 0\\ 12 & 8 & 16 & 0 & 1 & 0\\ 4 & 2 & 4 & 0 & 0 & 1\end{matrix}\right]\] That's how I do it. (There's probably an easier way..)
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
Hmm, is that 3 in a_11 positive or negative?
 one year ago

iop360Best ResponseYou've already chosen the best response.0
this is where im at now\[\left[\begin{matrix}1 & 0 & 0 & 0 & \frac{ 1 }{ 4} & 1 \\ 0 & 1 & 2 & 0 & \frac{ 1 }{ 2 } & \frac{ 3 }{ 2 } \\ 0 & 0 & k & 1 & \frac{ 3 }{ 4 } & 3\end{matrix}\right]\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
how would i express k on the inverse matrix
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
Continue to reduce it using row operations until you have only the identity matrix on the left.
 one year ago

iop360Best ResponseYou've already chosen the best response.0
could i multiplay R3 by 1/k?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
Looks like you have to.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
The last step ought to be subtracting your new R3 from R2.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.2
*Sorry, twice R3 from R2..
 one year ago
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