krissywatts
i need help solving the following? to get the bearing of AB
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krissywatts
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kevin.chaithanya
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Subtract 75degrees from 90degrees and that is the bearing of AB
kevin.chaithanya
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krissywatts
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okay and can you help me with one more?
kevin.chaithanya
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That is the bearing of AB with north direction...is that what you want?
krissywatts
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for this one i neeed azimuth and bearing?
krissywatts
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i believe so
kevin.chaithanya
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Give your next problem and I'll clarify it
krissywatts
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krissywatts
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it ask me what is the azimuth of cd and what is the bearing of cd
kevin.chaithanya
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They must have given you a reference line or a starting line to find bearing and azimuth...
kevin.chaithanya
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Yes, I got it...they gave you north as reference line because both of your diagrams of N mentioned...So,the answer to the first problem is 15 degrees(as said). In the second problem, the bearing and reference are the same..140degrees 39seconds
krissywatts
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how did you get that? cause i'm trying to learn it and i don't know what i'm doing
kevin.chaithanya
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kevin.chaithanya
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Azimuth is the angle measured clock-wise from the reference line..
krissywatts
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oh okay
kevin.chaithanya
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krissywatts
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i have like front and back pages to do on this
krissywatts
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so i might come back later today
kevin.chaithanya
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That is bearing....bearing is measured from east side and west side from the reference line...So, bearing can be a maximum of 180 degrees but azimuth can be a maximum of 360 degrees
krissywatts
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okay
krissywatts
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so would i get 129.35?
krissywatts
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as the bearing?
kevin.chaithanya
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In the second problem, both bearing and azimuth are the same....90+50.39 = 140.39
kevin.chaithanya
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