i need help solving the following? to get the bearing of AB

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i need help solving the following? to get the bearing of AB

Mathematics
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|dw:1349501096990:dw|
Subtract 75degrees from 90degrees and that is the bearing of AB
|dw:1349501563244:dw|

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okay and can you help me with one more?
That is the bearing of AB with north direction...is that what you want?
for this one i neeed azimuth and bearing?
i believe so
Give your next problem and I'll clarify it
|dw:1349501712350:dw|
it ask me what is the azimuth of cd and what is the bearing of cd
They must have given you a reference line or a starting line to find bearing and azimuth...
Yes, I got it...they gave you north as reference line because both of your diagrams of N mentioned...So,the answer to the first problem is 15 degrees(as said). In the second problem, the bearing and reference are the same..140degrees 39seconds
how did you get that? cause i'm trying to learn it and i don't know what i'm doing
|dw:1349502315527:dw|
Azimuth is the angle measured clock-wise from the reference line..
oh okay
|dw:1349502449201:dw|
i have like front and back pages to do on this
so i might come back later today
That is bearing....bearing is measured from east side and west side from the reference line...So, bearing can be a maximum of 180 degrees but azimuth can be a maximum of 360 degrees
okay
so would i get 129.35?
as the bearing?
In the second problem, both bearing and azimuth are the same....90+50.39 = 140.39
|dw:1349502901633:dw|

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