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|dw:1349501096990:dw|

Subtract 75degrees from 90degrees and that is the bearing of AB

|dw:1349501563244:dw|

okay and can you help me with one more?

That is the bearing of AB with north direction...is that what you want?

for this one i neeed azimuth and bearing?

i believe so

Give your next problem and I'll clarify it

|dw:1349501712350:dw|

it ask me what is the azimuth of cd and what is the bearing of cd

They must have given you a reference line or a starting line to find bearing and azimuth...

how did you get that? cause i'm trying to learn it and i don't know what i'm doing

|dw:1349502315527:dw|

Azimuth is the angle measured clock-wise from the reference line..

oh okay

|dw:1349502449201:dw|

i have like front and back pages to do on this

so i might come back later today

okay

so would i get 129.35?

as the bearing?

In the second problem, both bearing and azimuth are the same....90+50.39 = 140.39

|dw:1349502901633:dw|