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Suppose your 1140kg sports car has a 280hp engine that's 40% efficient. (That is, 40% of the 280hp can be converted into the car's motion.)
Find the car's maximum speed after accelerating from rest for 3.1s .
So far I think the formula is v= P/F but the only thing throwing me of is the percentage of efficiency. Any help would be great. Thanks!
 one year ago
 one year ago
Suppose your 1140kg sports car has a 280hp engine that's 40% efficient. (That is, 40% of the 280hp can be converted into the car's motion.) Find the car's maximum speed after accelerating from rest for 3.1s . So far I think the formula is v= P/F but the only thing throwing me of is the percentage of efficiency. Any help would be great. Thanks!
 one year ago
 one year ago

This Question is Closed

HELLSGUARDIANBest ResponseYou've already chosen the best response.0
efficiency indicates in this case that out of maximum power (280 hp) only its 40% can be utilized..substitute the utilized power in the formula..can yo do it now?
 one year ago

naniboyBest ResponseYou've already chosen the best response.0
OMG!! That simple... lol WOW. Ok, thanks.
 one year ago
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