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 2 years ago
Suppose your 1140kg sports car has a 280hp engine that's 40% efficient. (That is, 40% of the 280hp can be converted into the car's motion.)
Find the car's maximum speed after accelerating from rest for 3.1s .
So far I think the formula is v= P/F but the only thing throwing me of is the percentage of efficiency. Any help would be great. Thanks!
 2 years ago
Suppose your 1140kg sports car has a 280hp engine that's 40% efficient. (That is, 40% of the 280hp can be converted into the car's motion.) Find the car's maximum speed after accelerating from rest for 3.1s . So far I think the formula is v= P/F but the only thing throwing me of is the percentage of efficiency. Any help would be great. Thanks!

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HELLSGUARDIAN
 2 years ago
Best ResponseYou've already chosen the best response.0efficiency indicates in this case that out of maximum power (280 hp) only its 40% can be utilized..substitute the utilized power in the formula..can yo do it now?

naniboy
 2 years ago
Best ResponseYou've already chosen the best response.0OMG!! That simple... lol WOW. Ok, thanks.
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