## mathew0135 2 years ago The base of solid "S" is the region enclosed by the parabola "y=36-25x^(2)" and the x-axis. Cross-sections perpendicular to the y-axis are squares. Find the Volume of the described solid "S".

1. mathew0135

I've come up with an answer of $\int\limits_{0}^{36} \pi((36-y)\div(25))$ Any one agree or disagree?

can u make draw your answer, i cant see it my conection is low :(

3. mathew0135

|dw:1349508324532:dw| A little wonky but readable.

it should be : |dw:1360048939561:dw|

ops,, sorry you are right.. |dw:1360049305963:dw|

because that function must be squared first

except to find area, without squared :)

so, i agree with u

what is the volume do u get ?

10. mathew0135

the final volume i got was ((648)(pi))/(25). not sure if that's correct

yea, v=(36^2)/50 (pi) = 648/25 (pi) you are correct

12. mathew0135

okay, i'll post if i get this one right or not :)

13. mathew0135

The correct answer was 2592/25, not sure how that works.