## A community for students. Sign up today

Here's the question you clicked on:

## anonymous 3 years ago The base of solid "S" is the region enclosed by the parabola "y=36-25x^(2)" and the x-axis. Cross-sections perpendicular to the y-axis are squares. Find the Volume of the described solid "S".

• This Question is Closed
1. anonymous

I've come up with an answer of $\int\limits_{0}^{36} \pi((36-y)\div(25))$ Any one agree or disagree?

2. RadEn

can u make draw your answer, i cant see it my conection is low :(

3. anonymous

|dw:1349508324532:dw| A little wonky but readable.

4. RadEn

it should be : |dw:1360048939561:dw|

5. RadEn

ops,, sorry you are right.. |dw:1360049305963:dw|

6. RadEn

because that function must be squared first

7. RadEn

except to find area, without squared :)

8. RadEn

so, i agree with u

9. RadEn

what is the volume do u get ?

10. anonymous

the final volume i got was ((648)(pi))/(25). not sure if that's correct

11. RadEn

yea, v=(36^2)/50 (pi) = 648/25 (pi) you are correct

12. anonymous

okay, i'll post if i get this one right or not :)

13. anonymous

The correct answer was 2592/25, not sure how that works.

14. RadEn

thought one.... :P maybe 648/25 convert to decimal's form, it can be = 25.92 or convert to mix fraction : |dw:1349590447689:dw|

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy