The base of solid "S" is the region enclosed by the parabola "y=36-25x^(2)" and the x-axis. Cross-sections perpendicular to the y-axis are squares. Find the Volume of the described solid "S".

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The base of solid "S" is the region enclosed by the parabola "y=36-25x^(2)" and the x-axis. Cross-sections perpendicular to the y-axis are squares. Find the Volume of the described solid "S".

Mathematics
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I've come up with an answer of \[\int\limits_{0}^{36} \pi((36-y)\div(25))\] Any one agree or disagree?
can u make draw your answer, i cant see it my conection is low :(
|dw:1349508324532:dw| A little wonky but readable.

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it should be : |dw:1360048939561:dw|
ops,, sorry you are right.. |dw:1360049305963:dw|
because that function must be squared first
except to find area, without squared :)
so, i agree with u
what is the volume do u get ?
the final volume i got was ((648)(pi))/(25). not sure if that's correct
yea, v=(36^2)/50 (pi) = 648/25 (pi) you are correct
okay, i'll post if i get this one right or not :)
The correct answer was 2592/25, not sure how that works.
thought one.... :P maybe 648/25 convert to decimal's form, it can be = 25.92 or convert to mix fraction : |dw:1349590447689:dw|

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