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mathew0135

  • 3 years ago

The base of solid "S" is the region enclosed by the parabola "y=36-25x^(2)" and the x-axis. Cross-sections perpendicular to the y-axis are squares. Find the Volume of the described solid "S".

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  1. mathew0135
    • 3 years ago
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    I've come up with an answer of \[\int\limits_{0}^{36} \pi((36-y)\div(25))\] Any one agree or disagree?

  2. RadEn
    • 3 years ago
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    can u make draw your answer, i cant see it my conection is low :(

  3. mathew0135
    • 3 years ago
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    |dw:1349508324532:dw| A little wonky but readable.

  4. RadEn
    • 3 years ago
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    it should be : |dw:1360048939561:dw|

  5. RadEn
    • 3 years ago
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    ops,, sorry you are right.. |dw:1360049305963:dw|

  6. RadEn
    • 3 years ago
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    because that function must be squared first

  7. RadEn
    • 3 years ago
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    except to find area, without squared :)

  8. RadEn
    • 3 years ago
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    so, i agree with u

  9. RadEn
    • 3 years ago
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    what is the volume do u get ?

  10. mathew0135
    • 3 years ago
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    the final volume i got was ((648)(pi))/(25). not sure if that's correct

  11. RadEn
    • 3 years ago
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    yea, v=(36^2)/50 (pi) = 648/25 (pi) you are correct

  12. mathew0135
    • 3 years ago
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    okay, i'll post if i get this one right or not :)

  13. mathew0135
    • 3 years ago
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    The correct answer was 2592/25, not sure how that works.

  14. RadEn
    • 3 years ago
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    thought one.... :P maybe 648/25 convert to decimal's form, it can be = 25.92 or convert to mix fraction : |dw:1349590447689:dw|

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