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draw it out again

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Other answers:

u need to evaluate that ? its w.r.t du , right ? which topic does this question belong ?
i need to solve this by using convollution theorem
it is a laplace transform
Laplace or Fourier ? F = Fourier generally
we r following th e book laplace transform by spiegel
and the topic is alpplications to differential equations by using inverse laplace
anyone got my answr
\(\large \frac{s}{5}\frac{5}{(s^2+9)(s^2+4)}= \quad \frac{s}{5}\frac{(s^2+9)-(s^2+4)}{(s^2+9)(s^2+4)}\) now just separate denominator. got it ?
don't include s. lets just do partial fraction for 1/(s^2+4)(s^2+9) after that we multiply s to both terms
hmmm then?
what vales of A and b u got ?
A=1/85 and B=1/25
how ! 1= A (s^2+4) + B (s^2+9) put s^2 = -9 1= A (-9+4) 1= A (-5) A = -1/5 got this ?
similarly find B
thats correct. so now u got where that 1/5 came from ?
got it
u r very helpfull
thanks a lot man!
welcome ^_^
thats just separation of variables, which step did u not get ?
(s^2+4)dy/ did the minus sign cancel out?
u r rite, even i don't see, how they got that + maybe printing mistake in book.....
my sir showed us a similar problem where the condition Y(0)=1,Y(pie)=0 and Y'(0)=c

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