anonymous
  • anonymous
|dw:1349516917936:dw|
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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hartnn
  • hartnn
draw it out again
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1349517106533:dw|

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hartnn
  • hartnn
u need to evaluate that ? its w.r.t du , right ? which topic does this question belong ?
anonymous
  • anonymous
i need to solve this by using convollution theorem
anonymous
  • anonymous
it is a laplace transform
hartnn
  • hartnn
Laplace or Fourier ? F = Fourier generally
anonymous
  • anonymous
we r following th e book laplace transform by spiegel
anonymous
  • anonymous
and the topic is alpplications to differential equations by using inverse laplace
anonymous
  • anonymous
anyone got my answr
anonymous
  • anonymous
?
hartnn
  • hartnn
\(\large \frac{s}{5}\frac{5}{(s^2+9)(s^2+4)}= \quad \frac{s}{5}\frac{(s^2+9)-(s^2+4)}{(s^2+9)(s^2+4)}\) now just separate denominator. got it ?
anonymous
  • anonymous
|dw:1349520425747:dw|
hartnn
  • hartnn
don't include s. lets just do partial fraction for 1/(s^2+4)(s^2+9) after that we multiply s to both terms
hartnn
  • hartnn
|dw:1349520610397:dw|
anonymous
  • anonymous
hmmm then?
hartnn
  • hartnn
what vales of A and b u got ?
anonymous
  • anonymous
A=1/85 and B=1/25
hartnn
  • hartnn
how ! 1= A (s^2+4) + B (s^2+9) put s^2 = -9 1= A (-9+4) 1= A (-5) A = -1/5 got this ?
hartnn
  • hartnn
similarly find B
anonymous
  • anonymous
B=1/5
hartnn
  • hartnn
thats correct. so now u got where that 1/5 came from ?
anonymous
  • anonymous
lol....
anonymous
  • anonymous
got it
anonymous
  • anonymous
u r very helpfull
anonymous
  • anonymous
thanks a lot man!
hartnn
  • hartnn
welcome ^_^
anonymous
  • anonymous
|dw:1349522140539:dw|
hartnn
  • hartnn
thats just separation of variables, which step did u not get ?
anonymous
  • anonymous
(s^2+4)dy/ds+sy=0....how did the minus sign cancel out?
anonymous
  • anonymous
|dw:1349522675157:dw|
anonymous
  • anonymous
|dw:1349522813018:dw|
hartnn
  • hartnn
u r rite, even i don't see, how they got that + maybe printing mistake in book.....
anonymous
  • anonymous
my sir showed us a similar problem where the condition Y(0)=1,Y(pie)=0 and Y'(0)=c

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