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koreanubBest ResponseYou've already chosen the best response.0
\[\int\limits_{?}^{?} \frac{ 1 }{ \sqrt{x}(1+x) }\]
 one year ago

koreanubBest ResponseYou've already chosen the best response.0
The question marks are not suppose to be there, so it's the problem without the question marks.
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
\int just use like this for integration ... seems like trig subs seems to work also changing 1 + x = (1 + i sqrt(x))(1  i sqrt(x)) and then taking partial fraction might work.
 one year ago

mukushlaBest ResponseYou've already chosen the best response.3
i believe usub will work
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
woops!! that also works!!
 one year ago

koreanubBest ResponseYou've already chosen the best response.0
For this exercise, I'm technically not suposed to use partial fractions
 one year ago

koreanubBest ResponseYou've already chosen the best response.0
I may be missing something, but I can't seem to find the answer with u = \[\sqrt{x} \]
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
change all x's into u's probably you would end up with 1/1+u^2 or something like that.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
You have to mess with the U a little bit kore :) but it will work.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
x= tan^2 theta might work
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
this is same as using trig subs x = tan^2 theta in original.
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
but lol ... we know int 1/1+x^2 = arctan (x) which is one of the standard integral.
 one year ago

koreanubBest ResponseYou've already chosen the best response.0
I got it! Yes!!! I was substituting the first \[\sqrt{x} \] in the integrand. Then, I realized that it gets canceled out. Thank you very much everyone! ... If it wasn't for you, I probably would have spent another 10 minutes on this. .
 one year ago
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