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koreanub
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?} \frac{ 1 }{ \sqrt{x}(1+x) }\]

koreanub
 2 years ago
Best ResponseYou've already chosen the best response.0The question marks are not suppose to be there, so it's the problem without the question marks.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0\int just use like this for integration ... seems like trig subs seems to work also changing 1 + x = (1 + i sqrt(x))(1  i sqrt(x)) and then taking partial fraction might work.

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.3i believe usub will work

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0woops!! that also works!!

koreanub
 2 years ago
Best ResponseYou've already chosen the best response.0For this exercise, I'm technically not suposed to use partial fractions

koreanub
 2 years ago
Best ResponseYou've already chosen the best response.0I may be missing something, but I can't seem to find the answer with u = \[\sqrt{x} \]

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0change all x's into u's probably you would end up with 1/1+u^2 or something like that.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0You have to mess with the U a little bit kore :) but it will work.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0x= tan^2 theta might work

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0this is same as using trig subs x = tan^2 theta in original.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0but lol ... we know int 1/1+x^2 = arctan (x) which is one of the standard integral.

koreanub
 2 years ago
Best ResponseYou've already chosen the best response.0I got it! Yes!!! I was substituting the first \[\sqrt{x} \] in the integrand. Then, I realized that it gets canceled out. Thank you very much everyone! ... If it wasn't for you, I probably would have spent another 10 minutes on this. .
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