A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
I need help with the bottom two integrals, top one is an example of how to do'em
http://i.imgur.com/vRAvJ.jpg?1
 2 years ago
I need help with the bottom two integrals, top one is an example of how to do'em http://i.imgur.com/vRAvJ.jpg?1

This Question is Closed

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0The questions are from the partial fractions section to clue you in on how to maybe go about this

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0The thing is I went further into this, but it got real hectic. The answer I got for the bottom left integral was similar to the answer, but not quite, not sure where I went wrong

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1I'll give you short answer of tan dw:1349542124538:dw

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1349542218574:dw

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1for the other one ... use weistrass subs ... doesn't look nice to me.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1349542384994:dw

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0Oh.. wow, see i don't have math vision like that wth. how do you even know. just you've done it so many times??

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1I've seen it couple of times.

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0that's the right answer for that one, but i have to use the substitutions given, when should I sub them in?

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0and what is "weistrass subs"

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1http://en.wikipedia.org/wiki/Weierstrass_substitution no matter what ... these substitutions always work ... if you can find nice answers from other method, don't use this.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1looks like you have simplified it so nicely ... dw:1349542787800:dw

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0i tried taking the 4 out so its 15/256 or something then doing the arctan thing

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0Buhaha, you took a picture of your notebook XD Nice handwriting at least c:

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1yeah that would even make it nicer. dw:1349542995485:dw

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0thnx zep, it's easier for you guys to see and understand the problem that way roflmao

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0It's bubbly like comic sans, and it's legible XD hehe

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1should be similar to it. not sure ... try working on paper ... doing here is like playing around. i never get it right.

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.01/(15/256) arctan [(u+1/8)/(sqrt (15/256))]

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0a^2 = 15/256 so a is sqrt(15/256) right

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0i g2g now, but thanks for all your help. if anyone leaves more detailed info that'd be great, i'll be back to check.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1I don't like Weierstrass either
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.