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\[f'(c)=\frac{f(b)-f(a)}{b-a}\]

I found my c to be 3.366 but the answer is wrong

a=1 and b=8

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yes, i know how to do it..but got it wrong.. don't know why

Does it want an approximation?

it didn't say..so i'm thinking should the answer be an exact number

(Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE).

but then i think there is only 1 number c

Well the number you put above is not the exact answer

That is call an appoximation

how do get an exact number?

So I assume you did the setup right because you got the approximation to the correct answer

This is the setup you chose?
\[\frac{1}{c}=\frac{\ln(8)-\ln(1)}{8-1}\]

yes

We know ln(1) =?
and 8-1=?
So can you tell me what 1/c=
Don't use your calculator

and then f'(c) = 1/c
then solve for c

ln 1 = 0
8-1= 7

Ok
we have
\[\frac{1}{c}=\frac{\ln(8)-0}{7}\]
Do you know how to solve this for c?

ln 8/ 7 = 1/c
c= 7/ln8

right

ok thanks so much!

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