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 2 years ago
how much work would it take for a 75 kg person to climb the 9000 meters from sea level to the peak of mount everest? how much potential energy wold this person have when he or she reached the summit? show yoour calculations
can somebody help me
 2 years ago
how much work would it take for a 75 kg person to climb the 9000 meters from sea level to the peak of mount everest? how much potential energy wold this person have when he or she reached the summit? show yoour calculations can somebody help me

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kappa007
 2 years ago
Best ResponseYou've already chosen the best response.0have you read the formula U = mgh ?

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1I'm not sure if can assume that g is constant. OK:\[Work= \Delta U\]U is potential energy. \[U=\frac{MmG}{r}\] \[\Delta U=\frac{MmG}{6353000+9000}(\frac{MmG}{6353000})\] http://www.wolframalpha.com/input/?i=%5Cfrac%7B5.97219%C3%9710%5E24+75+%286.67300+%C3%97+10%5E11%29%7D%7B6353000%2B9000%7D%28%5Cfrac%7B5.97219%C3%9710%5E24+*+75+%286.67300+%C3%97+10%5E11%29%7D%7B6353000%7D%29 So the work the gravitational field does is 6.65558131072543162062365316101183770926987440628 × 10^6, and the work you do is 6.65558131072543162062365316101183770926987440628 × 10^6 Using just U=mgh W=mg(h(2)h(1))=75*9.8*(9000)= 6615000 The error is 0.6%, so g is fine being constant.

nisa
 2 years ago
Best ResponseYou've already chosen the best response.0no it says if not told then assume g is 10 m/s^2
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