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how much work would it take for a 75 kg person to climb the 9000 meters from sea level to the peak of mount everest? how much potential energy wold this person have when he or she reached the summit? show yoour calculations
can somebody help me
 one year ago
 one year ago
how much work would it take for a 75 kg person to climb the 9000 meters from sea level to the peak of mount everest? how much potential energy wold this person have when he or she reached the summit? show yoour calculations can somebody help me
 one year ago
 one year ago

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kappa007Best ResponseYou've already chosen the best response.0
have you read the formula U = mgh ?
 one year ago

henpenBest ResponseYou've already chosen the best response.1
I'm not sure if can assume that g is constant. OK:\[Work= \Delta U\]U is potential energy. \[U=\frac{MmG}{r}\] \[\Delta U=\frac{MmG}{6353000+9000}(\frac{MmG}{6353000})\] http://www.wolframalpha.com/input/?i=%5Cfrac%7B5.97219%C3%9710%5E24+75+%286.67300+%C3%97+10%5E11%29%7D%7B6353000%2B9000%7D%28%5Cfrac%7B5.97219%C3%9710%5E24+*+75+%286.67300+%C3%97+10%5E11%29%7D%7B6353000%7D%29 So the work the gravitational field does is 6.65558131072543162062365316101183770926987440628 × 10^6, and the work you do is 6.65558131072543162062365316101183770926987440628 × 10^6 Using just U=mgh W=mg(h(2)h(1))=75*9.8*(9000)= 6615000 The error is 0.6%, so g is fine being constant.
 one year ago

nisaBest ResponseYou've already chosen the best response.0
no it says if not told then assume g is 10 m/s^2
 one year ago
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