anonymous
  • anonymous
Need help with finding four numbers! (Problem in comments)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Suppose you have four numbers (call them a,b,c,d). They have the following characteristics: a is a perfect cube b is a perfect square c is divisible by 10 d is ONLY divisible by 5 They are also related in the following ways: \[c-a=4+b\] \[d/c = (a-(d-51)/a-(c-69))\] \[bc-ad = 2165\] \[-5(d-3a) = 80\] What is a, b, c, and d?
anonymous
  • anonymous
Oh, and just so it doesn't cause any confusion, the second equation can also be written as: \[d/c = (a-(d-51)\div(a-(c-69))\]
anonymous
  • anonymous
well i'm doing some calculations...but i think one thing i know is that d is 5?

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anonymous
  • anonymous
how did you get d=5, joshi? I would just like to know how to start dealing with all of these.
anonymous
  • anonymous
oh wait never mind what i said about d. from c-a=4+b, i got c=4+b+a and i cross multiplied the second equation. and substituted c for 4+b+a that's what i have until now
anonymous
  • anonymous
Bahh...I'm just gonna give up on this stupid problem. Thanks for your help, though.
anonymous
  • anonymous
aw nooo well do you know the actual answer though? i'm going to finish this anyway, you're welcome

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