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mathstahp

  • 3 years ago

Need help with finding four numbers! (Problem in comments)

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  1. mathstahp
    • 3 years ago
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    Suppose you have four numbers (call them a,b,c,d). They have the following characteristics: a is a perfect cube b is a perfect square c is divisible by 10 d is ONLY divisible by 5 They are also related in the following ways: \[c-a=4+b\] \[d/c = (a-(d-51)/a-(c-69))\] \[bc-ad = 2165\] \[-5(d-3a) = 80\] What is a, b, c, and d?

  2. mathstahp
    • 3 years ago
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    Oh, and just so it doesn't cause any confusion, the second equation can also be written as: \[d/c = (a-(d-51)\div(a-(c-69))\]

  3. joshi
    • 3 years ago
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    well i'm doing some calculations...but i think one thing i know is that d is 5?

  4. mathstahp
    • 3 years ago
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    how did you get d=5, joshi? I would just like to know how to start dealing with all of these.

  5. joshi
    • 3 years ago
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    oh wait never mind what i said about d. from c-a=4+b, i got c=4+b+a and i cross multiplied the second equation. and substituted c for 4+b+a that's what i have until now

  6. mathstahp
    • 3 years ago
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    Bahh...I'm just gonna give up on this stupid problem. Thanks for your help, though.

  7. joshi
    • 3 years ago
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    aw nooo well do you know the actual answer though? i'm going to finish this anyway, you're welcome

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