Need help with finding four numbers! (Problem in comments)

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- anonymous

Need help with finding four numbers! (Problem in comments)

- schrodinger

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- anonymous

Suppose you have four numbers (call them a,b,c,d). They have the following characteristics:
a is a perfect cube
b is a perfect square
c is divisible by 10
d is ONLY divisible by 5
They are also related in the following ways:
\[c-a=4+b\]
\[d/c = (a-(d-51)/a-(c-69))\]
\[bc-ad = 2165\]
\[-5(d-3a) = 80\]
What is a, b, c, and d?

- anonymous

Oh, and just so it doesn't cause any confusion, the second equation can also be written as:
\[d/c = (a-(d-51)\div(a-(c-69))\]

- anonymous

well i'm doing some calculations...but i think one thing i know is that d is 5?

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- anonymous

how did you get d=5, joshi? I would just like to know how to start dealing with all of these.

- anonymous

oh wait never mind what i said about d.
from c-a=4+b, i got c=4+b+a
and i cross multiplied the second equation. and substituted c for 4+b+a
that's what i have until now

- anonymous

Bahh...I'm just gonna give up on this stupid problem. Thanks for your help, though.

- anonymous

aw nooo well do you know the actual answer though? i'm going to finish this anyway, you're welcome

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